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Chemical Chameleon

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by

Jocelyn Chay

on 16 April 2014

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Transcript of Chemical Chameleon

Apparatus
Procedure
Aim
Results
Chemical Chameleon
Oxidation - reduction reaction
of Potassium Permanganate (KMnO4) that initiates
colour change of the solution
INTRODUCTION
What is a
chemical reaction?
One form of substance
changing
to another form
Described through a chemical equation
Forming and breaking of chemical bonds
between atoms
Components of a
chemical reaction
Two types of
chemical reactions
Reactants
Reagents
Reaction can be divided into
sub-steps / elementary reactions
Spontaneous reaction
Non-spontaneous reaction
Occurs naturally, without extra energy
Occurs with the expenditure of extra
energy
EXPERIMENT
KMnO4 consists of
potassium, manganese, and oxygen
atom

Manganese atom is a
transition element
.
-
Multiple
oxidation state
- Each oxidation state will reflect certain
wavelength of light - which we perceive as
colours
Calculate the
ratio
of the elements
(potassium permanganate & sodium hydroxide) with respect to each other in a chemical reaction.

Form
differential equation
based on the results of the experiment.
Materials
Erlenmeyer flask, test tube, spatula,
electronic balance, measuring cylinder,
glass rod
Potassium permanganate, sodium hydroxide,
sucrose, distilled water

1. 0.06g of KMnO4 was dissolved in a few
ml of water in a test tube. Solution should
reach a level of 1.5cm from the mouth.

2. 100ml of water was poured into the
Erlenmeyer flask. 0.34g of solid NaOH and
1.41 g of sucrose was added into the flask.
All solid material was dissolved to obtain a
colorless solution.
3. Contents of test tube were poured into the
colorless solution and swirled, so that the
liquid is mixed well. The flask was left for
awhile and the color changes from purple to
yellow/brown were observed and recorded.

4. Steps 1 to 3 were repeated 3 times to get a
more accurate result.

5. Steps 1 to 3 were repeated again with double
the mass of solid NaOH used.
Procedure
Discussion
Permanganate is slowly reduced by sugar in alkaline environments.

The oxidation of the -C(H)(OH)- :
The speed of the reaction depends on the concentration of NaOH
When concentration is doubled (0.68g), reaction speeds up considerably.

In alkaline environments, permanganate ion is reduced to manganate ion.
Discussion
The blue color that formed during the chemical reaction is due the presence of both green permanganate and purple permanganate, while the red color that formed during the chemical reaction is due to the presence of both brown manganate and green permanganate.

When there is excess sugar, manganate is further reduced:

A colloidal solution of hydrous MnO2 (brown) is formed. Precipitate emerges after left for some time.
Purple -> Blue -> Green -> Red ->Brown
Video
by Isaac Haw
Malvin Seow
Ng Ming-Zhou
Ezleen Natasha
Jocelyn Chay

Calculation
The ratio of both reactants in the chemical reaction is
1:1
Amount of NaOH present after the purple permanganate is reduced to green permanganate :-
Therefore, the amount of NaOH reacted with KMnO4 is
0.02g.
Differential Equation
MA240 PROJECT
CONCLUSION
We managed to achieve the aim set for this experiment.

Ratio of the elements, potassium permanganate and sodium hydroxide is
1:1.

Differential equation :-




Differential Equation
Differential Equation
Differential Equation
There were some errors that came about because of impurities in the chemicals & condition of apparatus
Full transcript