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Transcript of Chemical Chameleon
Oxidation - reduction reaction
of Potassium Permanganate (KMnO4) that initiates
colour change of the solution
What is a
One form of substance
to another form
Described through a chemical equation
Forming and breaking of chemical bonds
Components of a
Two types of
Reaction can be divided into
sub-steps / elementary reactions
Occurs naturally, without extra energy
Occurs with the expenditure of extra
KMnO4 consists of
potassium, manganese, and oxygen
Manganese atom is a
- Each oxidation state will reflect certain
wavelength of light - which we perceive as
of the elements
(potassium permanganate & sodium hydroxide) with respect to each other in a chemical reaction.
based on the results of the experiment.
Erlenmeyer flask, test tube, spatula,
electronic balance, measuring cylinder,
Potassium permanganate, sodium hydroxide,
sucrose, distilled water
1. 0.06g of KMnO4 was dissolved in a few
ml of water in a test tube. Solution should
reach a level of 1.5cm from the mouth.
2. 100ml of water was poured into the
Erlenmeyer flask. 0.34g of solid NaOH and
1.41 g of sucrose was added into the flask.
All solid material was dissolved to obtain a
3. Contents of test tube were poured into the
colorless solution and swirled, so that the
liquid is mixed well. The flask was left for
awhile and the color changes from purple to
yellow/brown were observed and recorded.
4. Steps 1 to 3 were repeated 3 times to get a
more accurate result.
5. Steps 1 to 3 were repeated again with double
the mass of solid NaOH used.
Permanganate is slowly reduced by sugar in alkaline environments.
The oxidation of the -C(H)(OH)- :
The speed of the reaction depends on the concentration of NaOH
When concentration is doubled (0.68g), reaction speeds up considerably.
In alkaline environments, permanganate ion is reduced to manganate ion.
The blue color that formed during the chemical reaction is due the presence of both green permanganate and purple permanganate, while the red color that formed during the chemical reaction is due to the presence of both brown manganate and green permanganate.
When there is excess sugar, manganate is further reduced:
A colloidal solution of hydrous MnO2 (brown) is formed. Precipitate emerges after left for some time.
Purple -> Blue -> Green -> Red ->Brown
by Isaac Haw
The ratio of both reactants in the chemical reaction is
Amount of NaOH present after the purple permanganate is reduced to green permanganate :-
Therefore, the amount of NaOH reacted with KMnO4 is
We managed to achieve the aim set for this experiment.
Ratio of the elements, potassium permanganate and sodium hydroxide is
Differential equation :-
There were some errors that came about because of impurities in the chemicals & condition of apparatus