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Chapter 22 - Gauss' Law
Transcript of Chapter 22 - Gauss' Law
Apply to 3 problems
Sphere - Ex 22-3 (hollow), 22-4 (solid)
Sphere, nonuniform charge 22-5
Cylinder - Ex 22-6
Sheet - Ex 22-8
E = sigma/epsilon - Field of a large, infinite sheet, very important
Gaussian Surface should follow symmetry of problem
Electric field is zero in a conductor
E outside of sphere is the same as point charge (inside sphere is different, depends on if it's a conductor or insulator)
Nonuniform Concept 22-9
Applying Gauss' Law
Which surface has more flux through it?
Flux: Simple Examples
Assume each charge is q. What is the flux through surfaces 1, 2, and 3?
A Gaussian surface is a 3-dimensional, closed surface. It is an imaginary, mathematical construct. It does not really exist. But we use it as a tool to help us determine electric fields.
Light bulb analogy, if there is no light on INSIDE the bulb, how much flux is there through the surface?
Flux is a measure of a flow of a physical property through a surface
More flow = greater flux
If angle between flow and surface changes, flux changes
If area increases, flux increases (assuming uniform flux density
Φ = = q/ε0
We measure electric flux through a Gaussian surface
This means the area MUST be a closed surface
What is the direction of an area vector?
Area vector for a CLOSED surface always points out of surface