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Chapter 7 math copy
JR
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Josephine Roberts
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Updated Mar 13, 2021
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Chapters
00:00
Chapter 1
00:14
Chapter 2
00:42
Chapter 3
01:22
Chapter 4
01:29
Chapter 5
02:30
Chapter 6
04:02
Chapter 7
04:04
Chapter 8
05:08
Chapter 9
05:14
Chapter 10
06:03
Chapter 11
07:06
Chapter 12
07:08
Chapter 13
07:52
Chapter 14
07:54
Chapter 15
08:07
Chapter 16
08:09
Chapter 17
08:21
Chapter 18
08:26
Chapter 19
08:53
Chapter 20
09:07
Chapter 21
09:10
Chapter 22
09:31
Chapter 23
09:33
Chapter 24
Audio Transcript
Auto-generated
00:01 - 00:05
Hello, My name is Joe Zee, and today I'm going
00:05 - 00:08
to teach you about the three ways of solving systems
00:09 - 00:12
as well as the three different types of solutions for
00:12 - 00:14
system. So let's just jump into it.
00:16 - 00:21
The first way to solve the system is graphing, and
00:21 - 00:21
that is what.
00:22 - 00:24
And the way to do that is you take the
00:24 - 00:28
two equations in your systems and you graph those lines
00:29 - 00:32
and the point where those two lines meet, which is
00:33 - 00:33
I've pointed.
00:34 - 00:38
I've kind of pointed it out on the little picture
00:38 - 00:40
there. That is the solution.
00:42 - 00:43
So let's try an example.
00:44 - 00:48
Yeah, here we have the system three X plus two
00:49 - 00:55
y equals 12 and two x six x I minus
00:55 - 01:00
four y equals 12, and each block on the graph
01:01 - 01:01
is, too.
01:02 - 01:06
It's a little hard to secret small, but and the
01:06 - 01:12
point where those two lines meet is the access three
01:12 - 01:15
and the Y is 1.5.
01:17 - 01:21
Let's try the next system a solution way to solve
01:22 - 01:28
systems. Okay, so the next way to solve a system
01:28 - 01:30
is by substitution, which is this one.
01:31 - 01:36
So first you substitute for the given coordinates like it
01:36 - 01:41
will say y equals or X equals, And then the
01:41 - 01:44
other coordinate plus something.
01:45 - 01:48
And you will just put what y you're X equals
01:49 - 01:54
into, um, the like, two x or two y of
01:54 - 01:55
the first equation.
01:57 - 02:01
You are substituted it, and then you use the distributive
02:01 - 02:09
property to figure out what uh, that is, Then you
02:09 - 02:09
will solve the problem.
02:10 - 02:10
Algebraic Lee.
02:12 - 02:16
And then once you know what And once you have
02:16 - 02:19
one of the answers to x y you and put
02:20 - 02:25
it into the one of the equations and then you
02:25 - 02:27
will solve the equation and basically and then you will
02:27 - 02:28
have both answers.
02:29 - 02:30
Let's try an example.
02:34 - 02:37
And here we have the example I'm going to with
02:37 - 02:37
my clicker.
02:37 - 02:39
But you can't say that I'm gonna use my finger.
02:40 - 02:45
Um, here we have the example of four X plus
02:46 - 02:51
two y equals 20 and then beneath that we have
02:51 - 02:55
the thing that you are substituted for, which is we
02:55 - 02:59
have the given coordinate, which is why equals five X
03:00 - 03:00
minus two.
03:02 - 03:06
So we put but y equals into why into the
03:06 - 03:14
equation. So we have four x plus two five x
03:15 - 03:19
minus four equals 20 and if we use the distributive
03:20 - 03:25
property. We can turn that into for X plus 10
03:25 - 03:28
X minus eight equals 20.
03:29 - 03:35
Now, I can simplify that into 14 x fine.
03:35 - 03:37
Eight. By combining like terms.
03:38 - 03:41
And now we want to get rid of that, The
03:41 - 03:42
eight on that one side.
03:42 - 03:44
And so we're going to plus eight to both sides.
03:46 - 03:49
And so we'll have 14 x equals 28.
03:51 - 03:56
And now, if we divide each side of the equation
03:57 - 03:59
by 14, we won't get X equals two.
04:00 - 04:01
So now we know what X is.
04:02 - 04:03
Let's go to the next one.
04:04 - 04:08
Okay? And he was the second part of that example.
04:09 - 04:13
And so now we know what that X equals two.
04:13 - 04:13
So we have four.
04:15 - 04:15
Uh huh.
04:16 - 04:17
And so it was four X.
04:17 - 04:21
And now it is for two, Who plus two y
04:22 - 04:22
equals 20.
04:24 - 04:28
And so we can, uh, multiplies that.
04:28 - 04:35
And then we have eight equal eight plus to y
04:35 - 04:36
equals 20.
04:37 - 04:39
So if we ah uh huh.
04:40 - 04:44
Minus eight from both sides, we will have to y
04:44 - 04:45
equals 12.
04:46 - 04:51
And then once we we divide both sides by two
04:52 - 04:54
so we can isolate why we'll have y equals two.
04:56 - 04:58
And so answer it is.
04:58 - 05:02
It is X is to y equals sex.
05:04 - 05:05
So let next.
05:06 - 05:08
Let's try the next way to solve it.
05:09 - 05:13
The third way to solve a system is by culmination.
05:14 - 05:14
So what to go down?
05:16 - 05:21
So, um, if there are two ops, it's in a
05:21 - 05:24
system like four X and negative four X.
05:26 - 05:27
This is the method you would use.
05:29 - 05:33
You arrows subtract the system so they both eat.
05:34 - 05:37
So both of the opposites are zero because then you
05:37 - 05:39
only have the other one.
05:40 - 05:41
Then you solve the remaining problem.
05:41 - 05:47
Algebraic Bri So and then, since you have one of
05:48 - 05:51
the solutions you like part of the solution you input
05:51 - 05:55
into the other equation into or just one of the
05:55 - 06:00
equations and then you solve their own alphabetically too, so
06:00 - 06:01
you can know what those is.
06:02 - 06:03
So let's try the example.
06:06 - 06:07
So here we have the equation.
06:09 - 06:15
Um, seven X minus four y equals 16 and four
06:15 - 06:17
X minus four.
06:17 - 06:18
Y equals 32.
06:21 - 06:27
So, uh, here we have the both equations, we're adding
06:28 - 06:28
them together.
06:30 - 06:35
And so, uh, seven x plus five X equals 12
06:35 - 06:36
x and four y.
06:38 - 06:39
So it's negative for why?
06:39 - 06:43
Because, you know, I and then 16 plus 32 equals
06:43 - 06:47
48. And if we can simplify that down to, um
06:48 - 06:49
by taking out the zeal, because it's nothing.
06:50 - 06:54
So we have 12 x equals 48.
06:57 - 06:58
We divide both those style.
06:59 - 07:01
It's by 12 to isolate the X, and we have
07:02 - 07:03
X equals four.
07:04 - 07:06
Let's go on to the second poet of the example.
07:10 - 07:13
So now we know that X equals four.
07:14 - 07:18
So we have, um instead of five x, we have
07:18 - 07:25
54 plus for y equals 32.
07:26 - 07:29
So we so we multiply that and we have 20
07:30 - 07:36
plus four y equals 32 and then we minus and
07:36 - 07:37
to you from both sides.
07:39 - 07:43
So we have for why equals 12.
07:45 - 07:46
And then we divide both sides by forward to isolate
07:47 - 07:51
why and then we have y equals three.
07:55 - 07:56
And so we have it from here.
07:56 - 07:57
So we have.
07:59 - 08:03
Yeah, And so now we have the X equals four.
08:03 - 08:10
So first part of that is four, and the y
08:10 - 08:16
equals to the Saudi answer to the solution to that
08:16 - 08:19
system is for comma X.
08:20 - 08:21
That's the point.
08:23 - 08:26
And now let's talk about the three different types of
08:26 - 08:31
solutions, So oh, you have the three different types of
08:31 - 08:34
solutions. The one solution, which is the one that we
08:34 - 08:39
have been finding is when they're both different lines.
08:41 - 08:44
Mm. And they only pap us through each other once.
08:45 - 08:48
So the only point there was only one place where
08:49 - 08:49
they intersect.
08:50 - 08:54
So they only have one solution, and then we have
08:55 - 08:55
no solutions.
08:56 - 09:00
That is when the lines never never touch because they
09:00 - 09:04
are paler and because they will never touch.
09:05 - 09:06
They have no solutions.
09:09 - 09:10
And then we have infinite solutions.
09:12 - 09:14
That is when both lines overlap.
09:15 - 09:25
And so they yeah, overlapping for just for until the
09:26 - 09:27
line ends, which it doesn't.
09:27 - 09:30
So just they have infinite solutions.
09:35 - 09:36
So thank you.
09:36 - 09:39
That has been how to find solutions.
09:42 - 09:45
Two systems and the different types of solutions to systems.
09:46 - 09:47
Thank you.
09:47 - 09:47
And have a nice day.
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