Loading presentation...

Present Remotely

Send the link below via email or IM

Copy

Present to your audience

Start remote presentation

  • Invited audience members will follow you as you navigate and present
  • People invited to a presentation do not need a Prezi account
  • This link expires 10 minutes after you close the presentation
  • A maximum of 30 users can follow your presentation
  • Learn more about this feature in our knowledge base article

Do you really want to delete this prezi?

Neither you, nor the coeditors you shared it with will be able to recover it again.

DeleteCancel

Make your likes visible on Facebook?

Connect your Facebook account to Prezi and let your likes appear on your timeline.
You can change this under Settings & Account at any time.

No, thanks

Attack on Titan: Disproving Physics

No description
by

Edward Thompson

on 25 July 2013

Comments (0)

Please log in to add your comment.

Report abuse

Transcript of Attack on Titan: Disproving Physics

Super Tough Armin?
Scene 2
Height: 163 cm
Weight: 55 kg
What's Wrong
How to Fix
this Scene
Armin Arlelt
The Fall
Hitting the Wall
- No serious injuries
Force of Armin hitting the wall = 16,795.8 N

Force it takes to break a femur = ~4,000 N

25% chance of cracking ribs = ~3,300 N
- Reduce Armin's speed
when he was flying through the air
-Armin suffers from serious injuries
63kg
63kg
Assumed weight = 8kg
Attack on Titan:
Disproving the physics
Scene 1
The wall has gravity?
Explanation of what just happened
Calculations
How to Fix it
Why Physics was defied
Calculations
Scene 3
Sasha
Height: 168 cm
Weight: 55 kg

Assumptions:
It is impossible to do a front flip while running down a vertical surface and continue running down the wall

Samuel and Sasha were falling slower than the speed of gravity without any other forces acting against gravity
Her sudden deceleration with her anchors could have ripped her body in half
Sasha fell to about the height of 40m before stopping.
Gravity is the same as Earth's gravity
The wall is perfectly vertical
The assumed distances traveled are correct
The following information is correct
Let Samuel Die
The front flip was unnecessary, or she could have anchored herself to the wall while doing the front flip
Sasha immediately saving Samuel, as it takes Samuel 3.2 seconds to realistically fall 50m
Both Samuel and Sasha need to fall faster
Wall:50m tall
10m
20m
30m
40m
Samuel
Sasha
Distance from wall
25m
Δt=18 seconds
Samuel
Fg=(65kg)(9.8m/s)
Fg=637N[Down]
FA
Fg=(55kg)(9.8m/s)
Fg=539N[Down]
Applied Force
Normal Force
Free body diagrams
Sasha
Fg=(55kg)(9.8m/s)
Fg=539N[Down]
Applied Force
Normal Force
Sasha
Fg=(55kg)(9.8m/s)
Fg=539N[Down]
Applied Force
Normal Force
Sasha
??
Magic Force?
??
Magic Force?
??
Samuel
Fg=(65kg)(9.8m/s)
Fg=637N[Down]
FA
V1=0
Δt=0.6 seconds
Δd=2 meters
a=?

1m
Δd=v1Δt+0.5a(t)^2
(2m)=(0)Δt+0.5(a)(0.6)^2
2 = 0.5a(0.6)^2
a = 2/0.5(0.6)^2
a = roughly 11m/s^2
f=ma
f= 55kg * 11m/s^2
f= 605N
Wait... the numbers don't match up!
Δd=30m
Δt =18s
v1= 0
v2=?
a=-9.8m/s^2
Samuel
Fg=(65kg)(9.8m/s)
Fg=637N[Down]
FA
Δd=v1Δt+0.5a(t^2)
30m=(0)Δt+0.5(9.8m/s)(t)^2
30=-4.9(t)^2
t=(30/4.9)^1/2
t= roughly 2.5s
Solving for time
Sasha
Height: 168 cm
Weight: 55 kg

Solving for Acceleration
Δd=v1Δt+0.5a(t^2)
30m=0Δt+0.5a(18)^2
30=0.5a(324)
a=roughly 0.185m/s^2
Solving for Distance
Δd=v1Δt+0.5a(t^2)
Δd=(0)Δt+0.5(9.8)(18^2)
Δd=4.9(324)
Δd=1587.6m [Down]
The numbers don't make sense for Sasha either!
Δd=15m
Δt =6s
v1= 0
v2=?
a=?
Solving for Acceleration
Δd=v1Δt+0.5a(t^2)
15m=0Δt+0.5a(6)^2
15=0.5a(36)
a=roughly 0.83m/s^2
Fg=(55kg)(9.8m/s)
Fg=539N[Down]
Applied Force
Normal Force
Sasha
How long does it take for Samuel to reach the ground?
Δd=v1Δt+0.5a(t^2)
50m =(0)Δt+0.5(9.8)(t^2)
t=[2(50)/9.8]^1/2
t=roughly 3.2 seconds
Possibly inertia-less?
Why Physics was defied
Here Sasha is flying toward the ground at a high speed and is somehow able to stop and fly straight up perpendicular to the ground.
Angle of titan
Correct Path

Combined vector

Actual direction of Flight
9.8 m/s^2
47 degrees
Horizontal Acceleration = 9.8/tan47degrees
= 9.14m/s^2
Horizontal Force = ma
= 55kg * 9.14m/s^2
= 502.62N
Conclusion
Therefore it has been shown that it is impossible for her to be able to stop and go shooting straight up, when she was initially traveling at an angle of 47 degrees.
Calculations
Assumptions
Fg
Fg
Fa
Angle of Sasha to be 47 degrees
That it was not a trick of the camera angle
9.14m/s^2
Magic Force that shouldn't exist in this plane of reality
= not being able to get up afterwords
-fall acceleration = less than 9.8 m/s2
That information collected is correct
This mean that the Magic force that stopped Sasha was -737 N. But wait! This makes no sense at all. Remember!? Sasha was about half a meter off the ground when she stopped! So how was the force applied to her to slow down and stop?
(~7.41m/s2)
Combined Vector Force= a^2=(502.62)^2+ (55*9.8)^2
=252626.8644+290521
=Square root (543147.8644)
=736.98 or 737 N of force
-landed on tail bone
-no spinal injuries
-no fractures/sprains/etc.
No injuries from fall:
Conclusion
Thank you all for listening to us as we worked to disprove the Physics behind some scenes in Attack on Titan
Hope you enjoyed it!
& possibly being eaten by titans
-Armin is Superman
16,795.8 N is
nothing to me!
Assumptions Taken into Account:
Total mass (Armin + gear) = 63kg
Non-parabolic motion due to 3D maneuver gear
No air resistance
t=1.8s during the fall (its not 1 constant scene)
Gravity = 9.8m/s^2
-Change the amount
of time he took to fall
Calculations
Free-Body Diagrams
Full transcript