**Electrical Installation of Tourist Village**

Requirements

Lighting

Where:

N: Number of units

E: Required illumination

A: Floor area of room

: Luminaries efficiency

U.F: Utilization Factor

D.F: Depreciation Factor

Lw: Wattage of one unit

The Utilization Factor depends on:

1- Lighting distribution

2- Luminaries efficiency

3- Reflection of ceiling, wall and floor of the room

4- Room index

Methods of lighting calculation

Sockets

Software

Distribution Board

Types of Distribution Boards

**Air Condition**

**Team ( A )**

Lighting

Sockets

Abdelhamid Zaitoun

Transformer

Antenna System

The steps of lighting design

Main distribution boards

Sub distribution boards

Dr. Mohamed Mostafa

Prof.Dr. Mohamed Farahat

supervisors

Software

Area = 8 x 8 = 64 m²

H = 3 m

E = 100 lux

Room Index k = (a × b) / h (a + b) = (8 x 8)/ (3 x 16) = 1.33

From The Table

: U.F = 0.4036 and D.F = 0.8

Qgross = (E ×A)/ (U.F ×D.F) = (100 x 8 x 8) / (0.4036 x 0.8) = 19821.6 lm

Use (2X 18) Watt Lamps:

No of lamps = (Qgross /lumens) = 19821.6 /1350 = 14.6

=15 lamp

No Of Units = (No of lamps/no of lamps per Unit) = 15/2 = 7.5 =9 unit

Distribution (3x3)

Length Space to Height Ratio = 8/ (3x 3) = 0.88

Width Space to Height Ratio = 8/ (3 x 3) = 0.88

Accepted

Solved Example:

T.V Games

Each 40 m^2 contain one socket circuit.

Total area of each room=57.6m^2

Total VA=area*1000/40=57.6*1000/40=1440 VA

Let power socket=1

Let double power socket=0

VA of power socket=1*250=250 VA

VA of double power socket=0*500=0 VA

No of normal socket= (Total VA-VA of P.S-VA of D.P.S)/120

= (1440-250-0)/120=9

No of normal socket= 9

Taking40% emergency

No of emergency power socket=1

No of emergency double power socket= 0

No of emergency normal socket= 4

Solved Example:

Restaurant

⦁ Determine no of circuit of ( lighting and power socket in sec)

⦁ Determine total rated current

{(No of lighting circuits *5) & (no of power socket circuits *8)}

⦁ Calculate VA total = 220*I rated

⦁ Calculate current for main cable {VA/(380* )}

⦁ For safety consideration = 1.25*main cable current

⦁ Select the C.B ratted from table

⦁ Determined cable current for design = 1.2* IC.B

⦁ Select C.S.A stander from table

Steps of Calculation

Distribution Board

Total Power 3060 Watt

I = p/(v*p.f) = 3060/(220*.8) = 17.386 A

Max Current in lighting Circuit = 5 A

No of Circuit = 17.3863/5 = 3.477

Then 4 Circuits

Solved Example:

section (1)

Types of air conditioner

Window air conditioner

Split air conditioner

Central air conditioning system

Steps of Calculation

⦁ Determined total area of each room

⦁ Choose type of method ( FCU & AHU )

⦁ Use FCU if area is less than 100 m2

⦁ Use AHU if area is more than 100 m2

⦁ Calculate motor power

⦁ Design C.B & disconnected switch

Software

Ahmed Atef

Mohamed Adel

Abdelgawad Ayman

Ahmed Tolba

Mohamed Tolba

Mohamed Hamed

Ahmed Didamony

Eslam Saad

Ensaf Habeb

Ahmed Abdelwahab

Amir Mahmoud

Ahmed Lotfy

Lifts

Kitchen

Air Condition

Fire Alarm

Cable Tests

Earthing

P.F Correction

1- Determine lighting requirements

2- Select lamps and luminaries

3- Calculate number of luminaries required

4- Position the luminaries

5- Analysis the results (technical lighting features, costs)

Watts per square meter method

Point by point or inverse-square method

Lumen or light flux method

Steps of average illumination calculation using Lumen or light flux method

Types of Sockets

Normal sockets

Power sockets

Steps of Calculations

Each 40 m^2 contain one socket circuit

**Earthing**

In general any earthing system needs to satisfy three demands :

Lightning and short circuit

Safety

Equipment protection and functionality

There are five types of earthing system

TN-S earthing system

TN-C-S earthing system:

TT earthing system

IT system earthing

TN-c system earthing

1- Dimensions of the metallic electrode (length & diameters of electrode).

2- The type of soil (soil resistivity).

3- The contact between the earth and electrode.

4- The bonding of electrodes.

factors that effect on the resistance of earthing system

Rod's Specification:

L=3 m

d= 2.5 c.m (dimater of rod)

=100 .m (resistivity of rod)

For sphere electrode:-

Aeq = ln ( 8*l/d) = 2.2617

(K) is given n following table:

Since the standard of earth resistance

Earthing system of any building

R

earth=

100 / ( 2* *2.2617) = 7.0367

( of one electrode)

Iteration (1)

No . of rod in one side ( n ) = 3

Total no.of rod=(4 )=(4 )= 8

N =8

From table : k = 4.25

Assume D = 4 m (spacing between two rods)

increase no of rod to reduce

R

earth

Iteration (2)

n=4 , N=12 , K= 5.4

= 2.38 Ω

(not acceptable)

Iteration (3)

n=5

N=16 , K= 6

R

earth

= 1.92 Ω (acceptable) ------- end

Then number of rods needed is 5 rods with the previeous specification .

"You never fail until you stop trying"

Thank you ^_^

Normal sockets=120 VA

Power sockets=250-500 VA

Software

Software

software programs

Lumen method is used to compute the number of units required to produce a required average illumination. The number of units is found as follow:

**Transformer**

Main Parts of Distribution transformer

1-Iron Core

2-Windings

3-Low Voltage Windings

4-High Voltage Windings

5-Tank

6-Terminals

7-Tap Changer

8-Cooling Oil

Software

Classification of Distribution Transformers

According To Method of Insulating and Cooling

Oil Immersed Transformers

Dry -type transformer

There are different methods of transformer cooling according to its rating :

AN

AB

ON

OB

OFN

OFB

OW

OFW

N.B

Transformer calculations

Chalet loads:

Total VA of lighting = 3980 VA

Total VA of sockets = 10360 VA

Total VA of air- condition 26252 VA

Transformer (5&6&7)

* Diversity factors:

= 0.8 for lighting

= 0.5 for sockets

= 1 for air-condition

So total loads = (3980*0.8 + 10360 * 0.5 + 26252)

= 34616 VA

Taking 27 chalet feeding from one transformer

So total loads= 834.632 KVA

SO rating of transformer = (834.632 /0.9) = 927.368888 KVA

Standard ----------------- 1000 KVA

I ( rated )=total VA /380 =834.632 / 380 = 1268 A

I ( C.B ) = 1.25*1268 = 1585 A

SO ----- C.B = 2000 A

I (cable) = 1.2* I (C.B) = 1.2* 1585 = 1902 A

SO ----- C.S.A = (3*300 + 2*150) mm2

Generator calculations:-

Total emergency loads of 27 chalet = 243 KVA

SO ----- Rating of generator required = 250 KVA

For 81 chalet using :

3 Generator

3 transformer(5,6,7)

THANKS AND GRATITUDE

We thank Allah for the results that we have reached

For their supervision and great contribution to accomplish the work of this project

Then the supervisors:

Prof. Dr / Mohamed A.Farahat

&

Dr / Mohamed Mostafa Tawfik

The tourist village consists of :

Social building

: consists of 3 floors .

Block

: consists of 12 block each block consists of 6 floors each floor contains 4 flats.

Mall

: consists of 2 floors.

Chalet

: consists of 81 chalet each one consists of 2 floors each floor 2 flats.

The selection of the suitable lighting unit for each place .

The determination of the number of lighting units and it's distribution to achieve uniform lighting over working plane of each place.(social building , block, mall ,chalet)

We have plotted the resulted luminaires on

AutoCAD

program for obtaining lighting planes.

We design aprogram by

visual basic 2008

for lighting to give better and accurate design results.

The selection of the suitable types of sockets unit for each place .

The determination of the number of sockets units and it's distribution for each place.(social building , block, mall ,chalet)

The selection of the suitable circuit breakers and the cables which will feed the different loads of the village ( such as : lighting & socket loads and the power loads ) by using the standard C.B ratings and cable's C.S.A from the manufactures catalogues.

The selection of the suitable type of air conditioning for each place .

The selection of the rating of air condition components by the help of mechanical engineer .

The selection of suitable C.B and the cables which will feed the air condition using standard C.B rating and cables C.S.A from the manufacturers Catalogues.

The determination of the number of lifts required and the rating of the lifts motor for each building.

The selection of the suitable C.B and the cables which will feed the lifts D.B.

The determination of the kitchen loads .

The selection of the suitable C.B and cables which will feed the loads of kitchen .

Here

, we have calculated the rated transformer by means of knowing the drawn current from the project M.D.B panel , also by calculating the need KVA then we reached the rated KVA needed , also we loading of the transformer with only 90% of it's rated load .

In this section we have to improve the p.f from (about 0.8 lagging ) to be (

0.95 lagging

).

The compensating unit rating required for correcting the p.f determined.

Earthing networks are designed to fulfill a number of functions . They can be independent or operate together to provide one or more of

the following :

Safety of person with respect to electrical hazards.

Protection of equipment with respect to electrical hazards.

The suitable cable is chosen according to the following factors:

Current carrying capacity.

Voltage drops on cables.

Short circuit calculation.

Economics of cables .

So that ,

after calculating the needed C.S.A we check the voltage drop for each feeder to suitable percentage loss in voltage from source to the load , also the cable routs must be determined accurately for not making a large voltage drop.

We have selected the fire alarm detector according to the

nature

of the place that we need to project as in house for example the most common action that can happened is to have a fire that starts with smoke appearance first so we use smoke detectors and so on .

We need to design antenna system , this system is consist of

antenna

,

amplifier

,

distributer

and

tap-off

.

Lighting

Lighting Circuit

Autocad

Autocad

Autocad