### Present Remotely

Send the link below via email or IM

Present to your audience

• Invited audience members will follow you as you navigate and present
• People invited to a presentation do not need a Prezi account
• This link expires 10 minutes after you close the presentation
• A maximum of 30 users can follow your presentation

Do you really want to delete this prezi?

Neither you, nor the coeditors you shared it with will be able to recover it again.

### Make your likes visible on Facebook?

Connect your Facebook account to Prezi and let your likes appear on your timeline.
You can change this under Settings & Account at any time.

# Math Project Partial 1

No description
by

## Angela Garcia

on 5 September 2014

Report abuse

#### Transcript of Math Project Partial 1

Understanding the problem
4. A rock is thrown upward and its position function at any time is given by
S(t)=-16t^2+64t+96
Procedure
b. Graph the position function, showing at least 3 points where the rock is passing through.
S(t)=-16t^2+64t+96
Amanda López A01226974
Ángela García A01225986

a. Calculate the derivative of the position function using the limit definition

b. Graph the position function, showing at least 3 points where the rock is passing through

c. Given the velocity function v(t)=-32t+64. Graph this function, using at least 2 points

d. Given the acceleration function a(t)=-32. Graph this function, using at least 2 points

e. What is the connection between position – velocity – acceleration?

f. Calculate the time when the velocity is the half of the initial velocity
a. Calculate the derivative of the position function using the limit definition
f. Calculate the time when the velocity is the half of the initial velocity
Math Project Partial 1
c. Given the velocity function
v(t)=-32t+64.
Graph this function, using at least 2 points.
d. Given the acceleration function
a(t)=-32
. Graph this function, using at least 2 points
e. What is the connection between position – velocity – acceleration?
X Y
1 32
2 0
3 -32
4 -64
y = m x + b
V(t)=-32t+64
V(t)=-32(0)+64=64
V(t)=-32(1)+64=32
V(t)=-32(2)+64=0
V(t)=-32(3)+64=-32
V(t)= -32(4)+64=-64
(1,-32)
(2,-32)
s(0)=-16(0)^2+64(0)+96= 96
2(1)=-16(1)^2+64(1)+96= 144
s(2)=-16(2)^2+64(2)+96= 160
s(3)=-16(3)^2+64(3)+96= 144
s(4)=-16(4)^2+64(3)+96= 32
X Y
0 96
1 144
2 160
3 144
4 32
The formulas of the position, velocity and acceleration are very closely related because they are derivatives of one another.
If you derivate the formula for the position, you will obtain the velocity. If you derivate the formula for the velocity, you will obtain the acceleration.

S''(t)= a(t), S'(t)= v(t)
(1,32)
(0,64)
(0,96)
(1,144)
(2,160)
Flowchart
Full transcript