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Combined Gas Law

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Elvis Gong

on 16 January 2013

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Transcript of Combined Gas Law

By Xiaoli Liu, Donald Chen, Elvis Gong Combined Gas Law History & Theory Application Boyle's Law
-Found by Robert Boyle in 1662
-States that the volume of the gas at constant temperature is inversely proportional to the pressure of the the gas
- P1V1=P2V2 History & Theory Charles' Law
-Found by Jacques Charles in the 1780s
-States that the volume of a fixed amount of gas is proportional to the temperature in Kelvin Scale
-V1/T1 = V2/T2 Scuba Diving
-As the diver dive deeper into the water, the pressure of the gas inside the scuba tank will increase
-Temperature decreases as
the diver goes deeper
-As the pressure of the
scuba tank increases, the
volume of the gas will
decrease History & Theory Gay-Lussac's Law
-Found by Louis Gay-Lussac in the early 1800s
-States that the pressure of a constant amount of gas is proportional to the temperature of the gas
-P1/T1=P2/T2 Combined Gas Law -This law have no official founder
-It is a combination of Boyle's law, Charles' Law, and Gay-lussac's Law
-States that the pressure is inversely proportional to the volume, and the volume-pressure product is proportional to the temperature in Kelvin Scale Application Air Bags
-Air bags inflates by using a chemical reaction to rapidly change the temperature, volume, and pressure of the gas inside.
How does it work?
-1st, the conductor in the car will heat up to a certain temperature.
-This will ignite a certain
chemical inside the airbag
and creates high pressure
-As a result, the air bags
will rapidly inflate Application Weather Balloons
-Balloon is filled with gas that allows it to float
-As the balloon rise higher in
altitude, the temperature of
the air starts to decrease
-As a result, the pressure of
the gas inside the balloon will
decrease as the volume of
the gas increases because
they are inversely proportional
to each other Demonstration Quiz Time! If the pressure of a gas is initially 100 kPa and the volume of the gas is 39.6L at room temperature.
What is the final pressure of the gas if the temperature is 50.0K and the volume doesn't change? (Room temp. is 21 C) Question #1 Question #2 A gas have a volume of 0.600L at 245K.
What is the initial pressure if the temperature increases to 273K and the volume to 0.900L with a pressure of 101kPa ? Question #3 Name 1 Application of the Combined Gas Law and explain it Question #4 Who is the official founder of Combined Gas Law? Question #5 A 2.0L gas have a pressure of 10 kPa, and the temperature outside is -271C. If the temperature increases to 23K and the pressure decreases to 8.0 kPA. What is the final volume of the gas? Answer #1 Givens:
P1=100kPa P2=?
V1=39.6L V2=39.6L
T1=21 C T2=50.0K

convert 21C into K
temperature in C + 273 = temperature in K
21C +273 =294K
T1=294K Equation:
P1V1/T1 = P2V2/T2
isolate for P2
P2 = P1 V1 T2/ T1 V2 Answer
P1V1/T1 =P2V2/T2
0.60P1/245 = 0.90(101)/273
0.60P1/245 = 303/910
0.60P1 = 2121/26
P1 = 136kPa Calculations:
P2 = (100)(39.6)(50.0)/(294)(39.6)
P2 = 17.0kPa Therefore the final pressure of the gas is 17.0kPa Answer 5 Givens:
V1=0.600L V2=0.900L
T1=245K T2=273K
P1=??? P2=101kPa The final Pressure of the gas is 136 kPa 10(2.0)/2.0=V2(8)/23
V2= 29L P1V1/T1=P2V2/T2 Answer # 3 -Air Bags
-Weather Balloons
-Scuba Diving Answer NO ONE!
Because the Combined Gas Law have no official founder V1 =2.0L V2=???
P1=10kPa P2=8.0kPa
T1=2.0K T2=23K The final volume of the gas is 29L
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