Matrix Partners preso! Harvard Business Review How to lower the cost of enterprise sales? SOAR 101: Kiet Tran, Adrianna Barron, and Rainah Baet

Griffin

Pre-Cal / Period 4

18 April 2012 Our Story The Cost to Acquire a Customer (CAC) exceeds the Life Time Value (LTV) a customer brings us. This is my third go-around selling to large enterprises, SkyStream, Kontiki and now Qumu.

I like to explain to you the problem the way I see it, the changes I suggest to avoid making the same mistake again. and Travels to Clients Travels to clients to get to know them

Build report over lunch, dinner & golf events

Uses Social Media to find new leads

Closes deals face-to-face to relay commitment ` SlideRocket a-synchronous selling tool LinkedIn as a Sales Tool EchoSign - eSignatures for contracts Step 4: Implement a weekly training program Tools Organize Latest in asynchronous selling tools Ɵ θ Θ Θ 32. If i = -1, then 4i(6i) 1. 4i(6i) 2. 24i - Write orginal equation - Multiply 4i and 6i 3. 24(-1)

4. -24; C - Subsitute ( -1) - Solve 32. Given p || q

m n

m<1=75 1 2 m n q p What is m<2? || . 75 75 . . 180

- 75 105 . Geometry hyp=28 theta=24 . SOH

CAH

TOA Pascal's Triangle = 1(3y) (-1) 0 4 + 4(3y) (-1) + 6(3y) (-1) + 4(3y) (-1) + 1(3y) (-1) 3 1 2 2 1 3 0 4 = 81y + 4(27y ) (-1) + 6(9y )(1) + 4(3y)(-1) + 1 4 3 2 = 81y + (-108y ) + 54y + (-12y) + 1 4 3 2 = 81y - 108y + 54y - 12y + 1 3. For a wedding, Shereda bought several dozen roses and several dozen carnations. The roses cost $15 per dozen, and the carnations cost $8 per dozen. Shereda bought a total of 17 dozen flowers and paid a total of $192. How many roses did she buy? A. 6 dozen B. 7 dozen C. 8 dozen D. 9 dozen 1) 15r + 8c = 192 r + c = 17 -Write down linear equation

-8(r + c = 17) -Obtain coefficients that differ in sign

-8r + -8c = -136 -Multiply

15r + 8c = 192 -Set up linear equation elimination

+-8r + -8c = -136

7r + 0c = 56 -Add same terms

5) 7r = 56

7 7 -Divide

6) r = 8 roses cost $15 per dozen

carnations cost $8 per dozen

total of 17 dozen flowers

total of $192 C Algebra II D 9. Which figure can serve as a counterexample to the conjecture below? If one pair of opposite sides of a quadrilateral is parallel, then the quadrilateral is a parallelogram. A. Rectangle B. Rhombus C. Square D. Trapezoid D A 1 2 Kiet Tran

Adrianna Barron

Rainah Baet

Griffin

Pre-Cal / Period 4

18 April 2012 A 4 3 2 - - AMBASSADORS

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# Algebra II & Geometry Review

Adrianna, Kiet, & Rainah