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# Limiting Reactant

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## Lisa Sunshine

on 26 April 2012

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#### Transcript of Limiting Reactant

Limiting Reactant Determines what is going to STOP the reaction. Reactants can be: Limiting Reactant:
Used up in a reaction.
Determines the final amount of product that will be produced.
None leftover.
Excess Reactant:
added to ensure that the other reactant is completely used up
cheaper & easier to recycle.
Leftovers.
How is limiting reactant determined? Step 1: Write a balanced equation Step 2: For each reactant, calculate the amount of product produced. (Pick one--preferably the one the question asks about.) Step 3: Smaller answer indicates the limiting reactant. (It will also help you calculate the final amount of product!) EX: When copper (II) chloride reacts with sodium nitrate, copper (II) nitrate and sodium Chloride are formed. Step 1: Write the balanced equation CuCl + 2 NaNO --> Cu(NO ) + 2 NaCl 2 3 3 2 Step 2: Convert each reactant to the product. For this example, convert to.... If 15.0 grams of Copper (II) chloride react with 20.0 grams of sodium nitrate, how much sodium chloride can be formed? Sodium chloride 15.0 g CuCl 134.45 g CuCl 1 mol CuCl 1 mol CuCl 2 mol NaCl 1 mol NaCl 58.44 g NaCl 2 2 13.04 g NaCl produced
from 15.0 g CuCl 2 20.0 g NaNO 85.0 g NaNO 1 mol NaNO 2 mol NaNO 2 mol NaCl 1 mol NaCl 58.44 g NaCl 3 3 3 3 13.8 g NaCl produced from 20.0 g NaNO 3 Step 3: The smaller answer shows your limiting reactant. 13.0 is the smaller answer, so CuCl is the limiting reactanct and NaNO is the excess reactant. Sometimes you will be asked to determine how much excess is left over. Using the limiting reactant, convert to the mass of the excess reactant. Subtract the amount of excess consumed from the amount of excess given. 15.0 g CuCl 134.45 g CuCl 1 mol CuCl 1 mol CuCl 2 mol NaNO 2 2 85.0 g NaNO 1 mol NaNO 3 3 3 2 2 2 2 18.9 g NaNO used 3 20.0g NaNO - 18.9 used = 1.1 g NaNO leftover 3 3
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