Present Remotely

Send the link below via email or IM

• Invited audience members will follow you as you navigate and present
• People invited to a presentation do not need a Prezi account
• This link expires 10 minutes after you close the presentation

Do you really want to delete this prezi?

Neither you, nor the coeditors you shared it with will be able to recover it again.

THE PHYSICS OF CURLING

No description
by

Blair Johnson

on 3 March 2014

Report abuse

Transcript of THE PHYSICS OF CURLING

A GAME OF FRICTION
Curling depends on friction
Stone on ice
Broom on ice
Shoes on ice
Known coefficients of friction:
Stone on ice: 0.0168
Rubber on ice: 0.15
Movement of the broom can increase temperature of the ice by 1.5 degrees Celsius, reducing friction between the ice and stone

Coefficients of Friction
THE PHYSICS OF CURLING
Olympics
Non-Olympic Life
pt. 1 (same dir.)
Mass Blue Bowling Ball - 6.804kg
Mass Black Bowling Ball - 6.260kg
½ mv^2= ½mv^2+½mv^2 -- conservation of kinetic energy
added x and y vectors using Pythagorean Theorem for velocities after collision
Initial Kinetic Energy = 3.68j --> Final Kinetic Energy Sum = 2.39j
1.29j difference, amount lost to Friction/Heat
Explanation:
Unresurfaced ice
Rotational kinetic energy
Non-Olympic Life pt.2 (diff. dir.)
Mass Blue Bowling Ball - 6.804kg
Mass Black Bowling Ball - 6.260kg
½ mv^2= ½mv^2+½mv^2 -- conservation of kinetic energy
x vectors for velocity
initial kinetic energy: 4.697j
final kinetic energy: 1.482j
difference: 3.215j
Explanation:
at time of collision, there was a long enough duration that the first ball started to rotate, that rotation caused the second ball to rotate in the opposite direction, affecting its velocity (rotational kinetic energy)
unresurfaced ice
Olympics slash non-real
Goal: calculate mu of video, compare it to that of known mu
Force Friction=(mu)(m*g)
Force Friction = m*a
m*a=(mu)(mg) --> a=(mu)(g)
to find mu--acceleration of object divided by 9.8m/s/s
-0.1715=acceleration (loggerpro)
mu=(-0.1715)/(9.8m/s/s)= -(0.0175)
mu=0.0175
real mu of curling ice = 0.0168
difference -- .0007
percent error: -.04%
Non-Olympics
pt. 1 (same dir.)
Acceleration : 1.165m/s/s
a=(mu)(mg)
mass=6.804kg
g=9.8m/s/s
--> mu=a/g=1.165/9.8=.119
compared to real mu of .0168
difference = .102
experimental error: unresurfaced ice, kinetic rotational energy
mass curling stone: 17.2365kilograms
Pythagorean Theorem to add vectors V=sqrt(x^2+y^2)
½ mv^2= ½mv^2+½mv^2
before collision - 3.7255j
after collision - 2.224j
energy lost to heat/friction - 1.502j
Non-Olympics
pt. 2 (diff. dir.)
Elasticity of Collisions
2:25
:24
mass blue bowling ball: 6.804kg
acceleration: 1.275m/s/s
gravity: 9.8m/s/s
mu=a/g=1.275/9.8
mu=.130
compared to .0168
difference=.113
experimental errors, you know
Full transcript