### Present Remotely

Send the link below via email or IM

• Invited audience members will follow you as you navigate and present
• People invited to a presentation do not need a Prezi account
• This link expires 10 minutes after you close the presentation

Do you really want to delete this prezi?

Neither you, nor the coeditors you shared it with will be able to recover it again.

# 6.03 Calorimetry Honors

No description
by

## Erichelle Goitia

on 20 October 2014

Report abuse

#### Transcript of 6.03 Calorimetry Honors

6.03 Calorimetry Honors
Data Table
Distilled Water Volume: 205.0 mL
Constant Initial Temp: 24.5 degrees C
NaOH Mass: 2.535 g
Final Temp: 27.8 degrees C
Calculations
2. 535 x 1 mol/40 g = 0.063375 moles NaOH
Data & Observations
Part 2
Calculations
1. HCl + NaOH --> NaCl + H2O
2. 105 + 105 = 210 mL
210mL x 1 g/mL= 210 g
210 g x 4.184 J(28.2-25.2)= 2475 J
2475 J x 1 kJ/1000 J = 2.475 kJ
Erichelle Goitia
Part 1
Conclusion
1. NaOH + H2O --> NaOH
3. q = mc(T2-T1)
205 mL x 1 g/1ml = 205 g H2O
T2 = 27.8
T1= 24.5
27.8-24.5= 3.3
205 g x 4.184 J(3.3)= 2830 J

4. 2830J/0.063375 mol NaOH = 4.47 x 10^4 J/mol
4.74 x 10^4 J/mol x 1kJ/1000 J = 47.4 kJ/mol NaOH
3. 105 mL NaOH x 1L NaOH/1000 mL NaOH x 0.105 mol NaOH/1L NaOH = 0.0105 mol NaOH
4. 2.475 kJ/0.0105 mol NaOH = 235.7 kJ/mol
1a) NaOH + H2O --> NaOH
47.4 kJ/mol NaOH
b) HCl + NaOH --> NaCl + H2O
2.475 kJ
2) -47.4- (-44.2)/-44.2 = -2.07/-44.2 = -0.046 x 100 = 46 %
3) -56 - (-1.046)/-56= -1.0186/-56= -0.01819
x 100 = -1.819 %
4. Yes because the enthalpy change should double my prediction.
5. NaOH would need a high amount of energy to break apart because its an ionic bond. Ionic bonds are stronger than covalt bonds.
6. Since there's a gap, that mean heat would be escaping from that gap resulting in temperature loss. Decrease in temperature would also mean a decrease in enthalpy change.
HCl Solution: 105 mL
NaOH Solution: 105 mL
Initial HCl Temp: 25.2 degrees C
Mixed Solution Temp: 28.2 degrees C
Full transcript