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# Complex Analysis: Singularities and Casorati-Weierstrass Theorem (University of Leicester)

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Charalampidi Marianna

Christou Athanasia

Dimitriou Georgia

Loizidou Marina

Papadaki Ifigenia

Polykarpou Thekla

Stylianou Antri Singular Point

Singular point of a function f(z) is a point at which f(z) is not analytic.

A function f(z) is said to be analytic at some point z0 if it is differentiable at every point of a certain neighborhood of z0.

f(z) is analytic if and only if there exists a neighborhood N(z0;ε), ε>0 such that f’(z) exists for all zєN(z0;ε). Non-isolated singularity

A singular point z=z0 of a function f(z) is non-isolated if every neighborhood

of z0 contains at least one singularity of f(z) other than z0. Example:

1. f(z)= is nowhere analytic so that every point in is a

non-isolated singularity.

2. , the point z=0 is a non-isolated singularity

of Lnz since every neighborhood of z=0 contains points

on the negative real axis.

Principal part

Laurent Series Taylor Series Removable singularity

The principal part vanishes and the Laurent series is essentially a Taylor series. The series represents an analytic function in |z-z0|<R.

Example: = has an essential singularity at the origin. Essential singularity

The principal part has infinitely many non-zero terms.

Example: Examples:

1. f(z)= has 0 as an isolated singularity.

2. f(z)= has 2 as an isolated singularity. Isolated Singularity

Existence of a neighborhood of z0 in which z0 is the only singular point of f(z). with bk ≠ 0. Note: k=0 removable singularity

eg. f(z)=z

k=1 simple pole

eg. f(z)= 1/z Pole of order k

Pole is a type of singularity in which the Laurent expansion in the deleted neighborhood of z0 is

In general, if we multiply f(z) by (z-z0)m and take the limit z→z0, then Method of finding the order of a pole

If z0 is a pole of order k, then Example 2: Suppose that z0 is an essential singularity of a

function f, and let ω0 be any complex number.

Then, for any positive number ε,

|f(z)-ω0|< ε

is satisfied at some point z in each deleted

neighborhood of z0. Proof (by contradiction):

f is analytic in any deleted neighborhood of z0 and z0 is an essential singularity such that

0 <|z- z0|< δ, for some δ.

Claim: |f(z)-ω0|≥ ε, 0 <|z- z0|< δ for any z. Case 2:

If g(z0)=0, then g must have a zero of some finite order m at z0.

Define , ψ(z0) ≠ 0.

=>f has a pole of order m. Case 1:

If g(z0) ≠ 0, then , 0<|z-z0|<δ,

becomes analytic at z0 if .

=>z0 is a removable singularity of f. Define , 0 <|z-z0|< δ, which is bounded and analytic.

Hence, z0 is a removable singularity of g.

Let g be defined at z0 such that it is analytic there. Both cases lead to a contradiction. Hence our Theorem holds. Example 1:Full transcript

by

Tweet## Antri Stylianou

on 18 December 2012#### Transcript of Complex Analysis: Singularities and Casorati-Weierstrass Theorem (University of Leicester)

Charalampidi Marianna

Christou Athanasia

Dimitriou Georgia

Loizidou Marina

Papadaki Ifigenia

Polykarpou Thekla

Stylianou Antri Singular Point

Singular point of a function f(z) is a point at which f(z) is not analytic.

A function f(z) is said to be analytic at some point z0 if it is differentiable at every point of a certain neighborhood of z0.

f(z) is analytic if and only if there exists a neighborhood N(z0;ε), ε>0 such that f’(z) exists for all zєN(z0;ε). Non-isolated singularity

A singular point z=z0 of a function f(z) is non-isolated if every neighborhood

of z0 contains at least one singularity of f(z) other than z0. Example:

1. f(z)= is nowhere analytic so that every point in is a

non-isolated singularity.

2. , the point z=0 is a non-isolated singularity

of Lnz since every neighborhood of z=0 contains points

on the negative real axis.

Principal part

Laurent Series Taylor Series Removable singularity

The principal part vanishes and the Laurent series is essentially a Taylor series. The series represents an analytic function in |z-z0|<R.

Example: = has an essential singularity at the origin. Essential singularity

The principal part has infinitely many non-zero terms.

Example: Examples:

1. f(z)= has 0 as an isolated singularity.

2. f(z)= has 2 as an isolated singularity. Isolated Singularity

Existence of a neighborhood of z0 in which z0 is the only singular point of f(z). with bk ≠ 0. Note: k=0 removable singularity

eg. f(z)=z

k=1 simple pole

eg. f(z)= 1/z Pole of order k

Pole is a type of singularity in which the Laurent expansion in the deleted neighborhood of z0 is

In general, if we multiply f(z) by (z-z0)m and take the limit z→z0, then Method of finding the order of a pole

If z0 is a pole of order k, then Example 2: Suppose that z0 is an essential singularity of a

function f, and let ω0 be any complex number.

Then, for any positive number ε,

|f(z)-ω0|< ε

is satisfied at some point z in each deleted

neighborhood of z0. Proof (by contradiction):

f is analytic in any deleted neighborhood of z0 and z0 is an essential singularity such that

0 <|z- z0|< δ, for some δ.

Claim: |f(z)-ω0|≥ ε, 0 <|z- z0|< δ for any z. Case 2:

If g(z0)=0, then g must have a zero of some finite order m at z0.

Define , ψ(z0) ≠ 0.

=>f has a pole of order m. Case 1:

If g(z0) ≠ 0, then , 0<|z-z0|<δ,

becomes analytic at z0 if .

=>z0 is a removable singularity of f. Define , 0 <|z-z0|< δ, which is bounded and analytic.

Hence, z0 is a removable singularity of g.

Let g be defined at z0 such that it is analytic there. Both cases lead to a contradiction. Hence our Theorem holds. Example 1: