Loading presentation...

Present Remotely

Send the link below via email or IM

Copy

Present to your audience

Start remote presentation

  • Invited audience members will follow you as you navigate and present
  • People invited to a presentation do not need a Prezi account
  • This link expires 10 minutes after you close the presentation
  • A maximum of 30 users can follow your presentation
  • Learn more about this feature in our knowledge base article

Do you really want to delete this prezi?

Neither you, nor the coeditors you shared it with will be able to recover it again.

DeleteCancel

Make your likes visible on Facebook?

Connect your Facebook account to Prezi and let your likes appear on your timeline.
You can change this under Settings & Account at any time.

No, thanks

Roller Coaster Prezi

No description
by

Kevin-Mark Cruz-Sado

on 20 June 2013

Comments (0)

Please log in to add your comment.

Report abuse

Transcript of Roller Coaster Prezi

Roller Coaster Rules

Physics
Let's get Rollin'
Loop # 1
We decided that our would roller coaster consist of two loops one hump since it is a requirement. The main goal is to find the velocity of the marble at three different locations using two differnt methods
This loop is measured to be the four inches tall and seven inches wide. The marble passed through the loop successfully. Its pillar is nineteen inches tall.
On to the next one
The gap between the previous loop and the next loop is measured to be...
Loop # 2
The second loop is measured to have a height of four and a half inches and a width of five inches. The pillar is measured to have a height of twelve and a half inches
Keep going
Almost there
The Hump
The hump's height is 1 inch. The width is 2 inches. A pillar was not needed.
Ugi+Uki+Usi+Uti
W
Ugf+Ukf+Usf+Utf
0
0
0
0
0
0
Ugi= Ugf+ Ukf
m(10)h=(1/2)mv^2+m(10)h
(.177m)(10)=(1/2)v^2+10(.101)m
1.77m=(1/2)v^2+1.01m
1.52m=v^2
1.23=m/s
Ugi+Uki+Usi+Uti
W
Ugf+Ukf+Usf+Utf
Ugi+Uki=Ugf+Ukf
m(10)h+(1/2)mv^2=m(10)h+(1/2)mv^2
(.1143m)(10)+(1/2)(1.23)^2=(.1270m)(10)+(1/2)v^2
1.143m+2.270=1.270m+(1/2)v^2
.873=v^2
.934=v
W
Ugi+Uki+Usi+Uti
Ugf+Ukf+Usf+Utf
0
Uki=Ugf+Ukf
(1/2)mv^2=m(10)h+(1/2)mv^2
(1/2)(.0254m)(.934)^2=(.0508m)(10)(1/2)v^2
.01129=.508+v^2
.49671=v^2
.7047765=v
Soo...
I think I failed. I tried my best to do this but
hopefully I didn't fail... But most likely, I did
fail.
Fin.
The Model
Measurements
Full transcript