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PA6

Solución a problemas de tarea
by

SERGIO MARTINEZ

on 21 May 2013

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Transcript of PA6

Descomposición de fuerzas Sumatoria de fuerzas en X Sumatoria de fuerzas en Y Resultante Angulos Etiquetar fuerzas F1 F2 F3 alfa Tan alfa= 1/2 alfa = ang tan 1/2 alfa= 26.56 F1x = 0 F1y = +80 lb F2x = +160 cos 26.56 = 143.11lbs F2y = +160 sen 26.56 = 71.55 F3x = + 200 cos 45 = 141.42 lbs F3y = -141.42 lbs suma Fx = Rx = 0+143.11+141.42 = 284.53 lbs Suma Fy = Ry = +80+71.55-141.42 = 10.13 lbs R = (Rx2 + Ry2) R = (284.53) +(10.13) 2 2 284.71 lbs R Ry Rx
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