- the three gold seekers left fort Hudson on April 15, 1899. they had enough food and camping equipment for ten days.

-the trip by canoe from fort Hudson to point 1 takes three days.

-three is evidence that the three gold seekers climbed over mount Tempest. the east side of mount Tempest has a snow field that has to be crossed using snowshoes. after climbing the snow field the gold seekers would have left their snowshoes behind for the return journey. two pairs of snowshoes are still at the top of mount tempest.

-Fort Hudson is at the same elevation as point A. according to fort records, the average daily temperature during April 1899 was 4 C.

-on the west side of mount tempest two femur bones were found. they measure 40.9 cm 56.1cm in length

-when the bones were found, 98.6% of the carbon-14 remain.

4. A) How many metres above points B and C is the top of mount tempest, Point T?

B-C: are at the same elevation

C-T: approximately 2500m incline.

B) What was the mountain terrain like?

it has a lot of steep slopes and inclines on all the sides with a flat snowy peak.

5.A)How long would it take to travel from point B to mount tempest?

To travel from the campsite to the top of mount Tempest (5km) it would take the gold seekers about 5 and a half hours going at a pace of 0.9km/h

B) How long would it take to get from the peak to the lake?

The trip down the mountain (5.25km) would take them 1 hour and 20minuets apx. going at a pace of 4km/h

3. Is the path from point A to point B level?

yes because there are no countour lines showing an increase in elevation

6.What where the temperatures at the base and top of the mountain?

At the base of the mountain the average daily temperature was 4 degrees Celsius. At the top of the mountain at 3000m in altitude it is a temperature of -15.2 degrees celsius.

6. (equation)

T(A) = 4 - 0.0064A

T(3000) = 4 - 0.0064(3000)

T(3000) = 4 - 19.2

T(3000) = -15.2

7. Estimate the height of the people using the humerus bones you found.

-Scale 1 : 39.5

Sam Mason: 4.8cm

(4.8cm)(39.5cm)

189.6 cm

1.5m

Billy Pratt: 3.8 cm

(3.8cm)(39.5cm)

150.1cm

1.5m

Kittie Carmack: 3.6 cm

(3.6cm)(39.5cm)

142.2cm

1.4m

8. A)How old where the bones you found?

A(P) = -85.4p + 8541.1

A(P) = -85.4(98.6) + 8541.1

A(P) = -8420.44 + 8541

A(P) = 120.66

B) Bone 1:

Male:

m(x) = 2.38x + 61.41

m(x) = 2.38(40.9) + 61.41

m(x) = 97.34 + 61.41

m(x) = 158.75cm

1.6m

Female:

h(x) = 2.47x + 54.10

h(x) = 2.47(40.9) + 54.10

h(x) = 101.02 + 54.10

h(x) = 155.12cm

1.55m

Bone 2:

Male:

m(x) = 2.38x + 61.41

m(x) = 2.38(56.1) + 61.41

m(x) = 133.52 + 61.41

m(x) = 194.98cm

1.9m

Female:

h(x) = 2.47x + 54.10

h(x) = 2.47(56.1) + 54.10

h(x) = 138.57 + 54.10

h(x) = 192.67

1.9m

Bone 1 matches best to Billy Pratt when comparing all there heights with the heights we estimated.

Bone 2 almost definitely belongs to Sam Mason for its big length and the incredible height that the person would have been.

scenario:

At the beginning they all went in they canoe down stream for 3 days to reach point A (35,6) they then walked at the speed of 4km/h for 6 and a half hours to get to point B (11,9) which was there camp site. At they're campsite they would have slept and ate for around 10 hours or so before continuing on there long journey once again. In the morning they began they're trek up the mountain at a pace of 0.9 km/h to the peak and across the snow field that took 5 and a half hours. At mount tempest they removed they're snow shoes and proceeded down the mountain. Heading down hill at a speed of 4 km/h, which takes them an hour and twenty minuets. We found 2 remains including humerus bones approximately half way from Mt.Tempest to the lake. We have confirmed that the bones belonged to Sam Mason and Billy Pratt. We suspect that Kittie Carmack killed Sam Mason and Billy Pratt but weather or not it was done before or after they received the gold is to be determined. At honey lake we found a shovel and a hole in the ground meaning that there is a high chance that they obtained there treasures. We suspect that Kittie used the two men to get the treasure up the hill a ways but then got greedy and wanted all the gold for herself. But why did she kill them before getting it to the other end of the hill? Maybe she got nervous that they where starting to figure out her plan and to mount a counter attack. Who knows, but what happened to good ol Kittie Carmack? We think that she finished the climb by herself but realized that she did not have the power to row the canoe on a 3 day journey all the way back to Fort Hudson and even if she made it back there, they would obviously suspect something about what happened to the other two men. we suspect that she took all the food she had left and headed for a different fort to sell her gold collect her money and live the good life with all her money. But did she have enough food to make the trip either way, hard to tell. I guess we will never know for sure.

1. How long would it take the gold seekers to travel from point A to point B?

It would take the gold seekers around 6 and a half

hours to get from point A to point B (26km) at a pace of 4 km/h

2. Is the path from point A passing though point B to point C a straight line?

Yes, as you can see all the points for a linear relationship showing that its a straight line from point A to point C.

9. A) What is the equation of the line from A-B?

The coordinates of Point A and B are (35,6) and (11,9) therefore the slope of the line is -8 and the equation is

-8x+y-83=0

B)Write it in general form.

The equation of a line representing

moon river is perpendicular to the AB

line therefore it is: 1/8x+y-83=0

C)Another clue is found at (n,30) what is n?

The unknown coordinate on M.R is

y=86.75

Slope:

(y2-y1)/(x2-x1)

(11-35)/(9-6)

-24/3=-8

line equation:

y-y1=m(x-x1)

y-11=-8(x-9)

y-11=-8x+72

-8x+y-83=0

Pg 355 # 18

A)

B)

C)The Y intercept is 12°C and represents the temperature at sea level.

D) T(A)= -4/625A + 12

E) T = -4/625(5959) + 12

T = -26.1

F) Approximate 5000m

Perpendicular line:

1/8x+y-83=0

M.R point:

y=1/8(30)+83

y=3.75+83

y=86.75

Pg.312 #9

A)h=height in cm

L=length of humerus bone in cm

To find the height of a man, the function h(L)=2.9L+70.6

can be used when the length of his humerus bone is given.

if the length of his

humerus is 36.87cm

then his height would

be 177.5cm or 1.775m

B) For the height of a woman the function h(L)=2.8L+71.4

h(36.87) means that the length of her humerus bone was 36.87cm

h(36.87)=2.8(36.87)+71.4 Her height is 174.6cm

h(36.87)=174.6cm

C) The most likely range of heights for all people is between 120cm and 210cm, as it is unlikely that anyone would be taller than 210cm and shorter than 120cm

D) The span of values between the radius bone for a man is 10.12cm-37.45cm depending on his height. For a woman the span of values for a radius bone is 11.72cm-39cm.

E) My radius bone is 27cm long, and according to the function: h(L)=3.3L+86.4,

my height should be 175.5cm.

My actual height is 180cm

apx., so the function is fairly accurate

h(36.87)=2.9(36.87)+70.6

h36.87)=106.9+70.6

h(36.87)=177.5cm

h(27)=3.3(27)+86.4

h(27)=175.5

Pg.314 #13

A) No the graph is not linear, therefore it is not a function either.

B) Apx. 300 years have passed since the last buffalo jumped and bashed its head in.

C) About 50% of carbon-14 will be left in the bones after 5800 years.

**P.C MATH 10 Project, Unit 3**

Evidence Questions

Textbook Questions

B)Whose Bones where they?