Goal: Translate statements into algebraic expressions, and evaluate the expression 8.3 Creating and Evaluating

Expression Colin is helping to organize a school trip to Ottawa. He needs to figure out the cost of transportation and choose the least expensive bus company. A total of 260 students are going on the trip. He has prices from three bus companies for the cost of seven buses:

- Carry all bus company charges $350 per bus

- School bus transport charges $7 per student

- Zim transport charges $500 to cover the cost for the drivers plus $6 per student

- 260 Students

- Carryall bus company charges $350 per bus

-School bus transport charges $7 per student

-Zim transport charges $500 to cover the cost for the drivers plus $6 per student

Lets make an algebraic expression to solve the problem! What bus company should colin choose?

What information do we have? -260 Students/ 7 buses of students

-CarryAll bus company charges $350 per bus

-School bus transport charges $7 per student.

-Zim transport charges $500 to cover the cost for the drivers plus $6 per student.

First lets calculate the cost using the CarryAll bus company.

$350 X 7 = $2450

The cost will be $2450 to use the Carry all bus company. Solving the problem -260 students / 7 buses

-CarryAll bus company charges $350 per bus

-School bus transport charges $7 per student

- Zim transport charges $500 to cover the cost for the divers plus $6 per student.

Lets create an algebraic expression for School bus transport.

Lets use the variable s to represent the number of students going on the trip.

-$7 times 260 students

-we substitute 260 for s because 260 is the number of students going on the trip.

7s

=7(260)

=1820

Therefore school bus transport would cost $1820.

-260 student/ 7 buses

-CarryAll bus company charges $350 per bus.

-School bus transport charges $7 per student.

-Zim Transport charges $500 to cover the cost for the drivers plus $6 per student.

Lets make an expression for Zim Transport.

500+6s

=500+6(260)

=500 + 1560

=2060

-We used the variable s to represent the number of students going on the trip.

-we wrote an expression to represent multiplying s by $6 (the charge per student) and then adding $500 (The cost of the drivers)

- we substituted 260 for s because 260 is the number of students going on the trip.

-we used the order of operations to evaluate the expression.

Therefor Zim transport would charge $2060 for the buses.

Example #1 Question- Do you think that it would be easier to buy an ipad by paying an equal amount every month? or by putting down a deposit and then paying a lesser amount each month? Conclusion CarryAll Bus company cost $2450

School Bus transport cost $1820

Zim transport cost $ 2060

Colin should hire School Bus transport to go take the class to Ottawa!

1) why do you think colin did not use a table of values to find the cost for school Bus Transport or Zim Transport?

2) Why do you think that Colin did not use a scatterplot to find the cost for school Bus transport or Zim transport?

3) Explain how to create an algebraic expression. Homework!!! -Work with a partner and complete question 4-6.

-Individually complete 10,12 and 16.

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# 8.3 Creating and Evaluation Expressions

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