Goal: Translate statements into algebraic expressions, and evaluate the expression 8.3 Creating and Evaluating

Expression Colin is helping to organize a school trip to Ottawa. He needs to figure out the cost of transportation and choose the least expensive bus company. A total of 260 students are going on the trip. He has prices from three bus companies for the cost of seven buses:

- Carry all bus company charges $350 per bus

- School bus transport charges $7 per student

- Zim transport charges $500 to cover the cost for the drivers plus $6 per student

- 260 Students

- Carryall bus company charges $350 per bus

-School bus transport charges $7 per student

-Zim transport charges $500 to cover the cost for the drivers plus $6 per student

Lets make an algebraic expression to solve the problem! What bus company should colin choose?

What information do we have? -260 Students/ 7 buses of students

-CarryAll bus company charges $350 per bus

-School bus transport charges $7 per student.

-Zim transport charges $500 to cover the cost for the drivers plus $6 per student.

First lets calculate the cost using the CarryAll bus company.

$350 X 7 = $2450

The cost will be $2450 to use the Carry all bus company. Solving the problem -260 students / 7 buses

-CarryAll bus company charges $350 per bus

-School bus transport charges $7 per student

- Zim transport charges $500 to cover the cost for the divers plus $6 per student.

Lets create an algebraic expression for School bus transport.

Lets use the variable s to represent the number of students going on the trip.

-$7 times 260 students

-we substitute 260 for s because 260 is the number of students going on the trip.

7s

=7(260)

=1820

Therefore school bus transport would cost $1820.

-260 student/ 7 buses

-CarryAll bus company charges $350 per bus.

-School bus transport charges $7 per student.

-Zim Transport charges $500 to cover the cost for the drivers plus $6 per student.

Lets make an expression for Zim Transport.

500+6s

=500+6(260)

=500 + 1560

=2060

-We used the variable s to represent the number of students going on the trip.

-we wrote an expression to represent multiplying s by $6 (the charge per student) and then adding $500 (The cost of the drivers)

- we substituted 260 for s because 260 is the number of students going on the trip.

-we used the order of operations to evaluate the expression.

Therefor Zim transport would charge $2060 for the buses.

Example #1 Question- Do you think that it would be easier to buy an ipad by paying an equal amount every month? or by putting down a deposit and then paying a lesser amount each month? Conclusion CarryAll Bus company cost $2450

School Bus transport cost $1820

Zim transport cost $ 2060

Colin should hire School Bus transport to go take the class to Ottawa!

1) why do you think colin did not use a table of values to find the cost for school Bus Transport or Zim Transport?

2) Why do you think that Colin did not use a scatterplot to find the cost for school Bus transport or Zim transport?

3) Explain how to create an algebraic expression. Homework!!! -Work with a partner and complete question 4-6.

-Individually complete 10,12 and 16.

PAGE 280

### Present Remotely

Send the link below via email or IM

CopyPresent to your audience

Start remote presentation- Invited audience members
**will follow you**as you navigate and present - People invited to a presentation
**do not need a Prezi account** - This link expires
**10 minutes**after you close the presentation - A maximum of
**30 users**can follow your presentation - Learn more about this feature in our knowledge base article

Do you really want to delete this prezi?

Neither you, nor the coeditors you shared it with will be able to recover it again.

### Make your likes visible on Facebook?

Connect your Facebook account to Prezi and let your likes appear on your timeline.

You can change this under Settings & Account at any time.

# 8.3 Creating and Evaluation Expressions

No description

by

Tweet