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# Solving slope intercept, point-slope, and standard form

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Tweet## ashley coates

on 27 May 2011#### Transcript of Solving slope intercept, point-slope, and standard form

Step 1:

solving point slope equations. First you start out with

point-slope form:

y-y1=m(x-x1) Part one: point-slope form next you have your ordered pairs such as

(3,2) and (1,4) next you find your m, or slope by using the equation

y2-y1

x2-x1 now, pick an ordered pair and use that and your slope to plug them into the equation y-y1=m(x-x1) using the ordered pair (3,2) and the slope -1

y-2=-1(x-3)

and that's point-slope form. so your equation will be

4-2

1-3 4-2 =2

1-3 =-2 this is simplifies to -1 Lets try a problem:

coordinate points: (3,10) and (2,5) answer:

y-10=5(x-3) Explanation:

5-10

2-3

this equals 5 (your slope)

next, plug the coordinate point of your choice and the slope into the equation lets try a couple more: 1. (2,7),(4,1) 2. (3,8),(4,6) 3. (10,7),(6,3) Part two: standard form step one: solving standard form equations first, you take two coordinate points and put them in point-slope form. standard form is the equation

Ax+By=C (3,1) (4,2)

2-1

4-3

which simplifies to 1

y-2=1(x-4)

this is NOT your answer

only a step into getting your answer next you simplify the equation,like this:

y-2=1(x-4)

*distribute the one to the x and the four

1(x)-1(-4)

y-2=1x-4

*next subtract 1x from each side

y-2 = 1x-4

-1x -1x

-1x-1y-2=-4

+2 +2

*now you add 2 to each side which is called the inverse operation because it is the opposite.

your answer should be:

-1x-1y=-4 1-7

4-2

=-4

y-1=-4(x-4)

-or-

y-7=-4(x-2) 6-8

4-3

=-2

y-8=-2(x-3)

-or-

y-6=-2(x-6) 3-7

6-10

=1

y-7=1(x-10)

-or-

y-3=1(x-6) now that you know how to write an equation in standard form,why dont you try a couple on your own put the equations into standard form:

1.)y-6=2(x-4) 2.)y-3=1/2(x-8) 3.)y+3=2(x-1) 1.) y-6=2x-8

-2x -2x

-2x-1y-6=-8

+6 +6

-2x-1y=-2 2.)y-3=1/2x-4

-1/2x -1/2x

-1/2x-y-3=-4

+3 +3

-1/2x-y=-1 3.)y+3=2(x-1)

y+3=2x-2

-2x -2x

-2x+y+3=-2

-3 -3

-2x+1y=-5 i hope this was easy to understand and helped.

Full transcriptsolving point slope equations. First you start out with

point-slope form:

y-y1=m(x-x1) Part one: point-slope form next you have your ordered pairs such as

(3,2) and (1,4) next you find your m, or slope by using the equation

y2-y1

x2-x1 now, pick an ordered pair and use that and your slope to plug them into the equation y-y1=m(x-x1) using the ordered pair (3,2) and the slope -1

y-2=-1(x-3)

and that's point-slope form. so your equation will be

4-2

1-3 4-2 =2

1-3 =-2 this is simplifies to -1 Lets try a problem:

coordinate points: (3,10) and (2,5) answer:

y-10=5(x-3) Explanation:

5-10

2-3

this equals 5 (your slope)

next, plug the coordinate point of your choice and the slope into the equation lets try a couple more: 1. (2,7),(4,1) 2. (3,8),(4,6) 3. (10,7),(6,3) Part two: standard form step one: solving standard form equations first, you take two coordinate points and put them in point-slope form. standard form is the equation

Ax+By=C (3,1) (4,2)

2-1

4-3

which simplifies to 1

y-2=1(x-4)

this is NOT your answer

only a step into getting your answer next you simplify the equation,like this:

y-2=1(x-4)

*distribute the one to the x and the four

1(x)-1(-4)

y-2=1x-4

*next subtract 1x from each side

y-2 = 1x-4

-1x -1x

-1x-1y-2=-4

+2 +2

*now you add 2 to each side which is called the inverse operation because it is the opposite.

your answer should be:

-1x-1y=-4 1-7

4-2

=-4

y-1=-4(x-4)

-or-

y-7=-4(x-2) 6-8

4-3

=-2

y-8=-2(x-3)

-or-

y-6=-2(x-6) 3-7

6-10

=1

y-7=1(x-10)

-or-

y-3=1(x-6) now that you know how to write an equation in standard form,why dont you try a couple on your own put the equations into standard form:

1.)y-6=2(x-4) 2.)y-3=1/2(x-8) 3.)y+3=2(x-1) 1.) y-6=2x-8

-2x -2x

-2x-1y-6=-8

+6 +6

-2x-1y=-2 2.)y-3=1/2x-4

-1/2x -1/2x

-1/2x-y-3=-4

+3 +3

-1/2x-y=-1 3.)y+3=2(x-1)

y+3=2x-2

-2x -2x

-2x+y+3=-2

-3 -3

-2x+1y=-5 i hope this was easy to understand and helped.