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Solving slope intercept, point-slope, and standard form
Transcript of Solving slope intercept, point-slope, and standard form
solving point slope equations. First you start out with
y-y1=m(x-x1) Part one: point-slope form next you have your ordered pairs such as
(3,2) and (1,4) next you find your m, or slope by using the equation
x2-x1 now, pick an ordered pair and use that and your slope to plug them into the equation y-y1=m(x-x1) using the ordered pair (3,2) and the slope -1
and that's point-slope form. so your equation will be
1-3 4-2 =2
1-3 =-2 this is simplifies to -1 Lets try a problem:
coordinate points: (3,10) and (2,5) answer:
this equals 5 (your slope)
next, plug the coordinate point of your choice and the slope into the equation lets try a couple more: 1. (2,7),(4,1) 2. (3,8),(4,6) 3. (10,7),(6,3) Part two: standard form step one: solving standard form equations first, you take two coordinate points and put them in point-slope form. standard form is the equation
Ax+By=C (3,1) (4,2)
which simplifies to 1
this is NOT your answer
only a step into getting your answer next you simplify the equation,like this:
*distribute the one to the x and the four
*next subtract 1x from each side
y-2 = 1x-4
*now you add 2 to each side which is called the inverse operation because it is the opposite.
your answer should be:
y-3=1(x-6) now that you know how to write an equation in standard form,why dont you try a couple on your own put the equations into standard form:
1.)y-6=2(x-4) 2.)y-3=1/2(x-8) 3.)y+3=2(x-1) 1.) y-6=2x-8
-2x+1y=-5 i hope this was easy to understand and helped.