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Remember the find the derivative of the function to begin constructing the slope field.
If you are having trouble figuring out how to evaluate for the slope, try constructing a table.
y= x^2 + 3
y' = 2x
This slope field will be based entirely on the value of x.
2
1
-1 1 2
f'(1) = 2 f'(-1) = -2
f'(0) = 0 f'(1) = 2
dy/dx = 2(y^2)(x^2)
Solve for f'(x).
First separate the variables in terms of y and x
Integrate both sides of the equation using basic rules of integration
Solve for y using basic algebra
dy/dx = 2(y^2)(x^2)
Step 1: Separate the variables in terms of x and y
dy/y^2 = *2x^2)(dx)
Step 2: Integrate both sides
int(dy/y^2) = int((2x^2)(dx))
: -1/y = ((2x^3)/3) + C (Only put +C on the right)
Step 3: Solve for y
-1 = (((2x^3)/3) + C)*y
y = -1/((2x^3)/3)+C