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Students predict the shape of a graph of a linear equation by finding and plotting solutions on a coordinate
plane.
Arranged in or extending along a straight or nearly straight line.
To mark (a route or position) on a chart
x - 5y = 11
X can be any random number but lets stick to a simple numb...
x - 5y = 11
X can be any random number but lets stick to a simple number.
x = 0
x = 1
x = 2
0 - 5y = 11
Therefore, y = - 11/5
so or points are (0,-11/5)
1 - 5y = 11
Therefore, y = -2
so our points are (1,-2)
Can the following points be on the graph of the equation x + y = 2
So, What are my points?
(- 1, 3)
(0,2)
(1,1)
(2,0)
(3,-1)
Lets plug it in
x + y = 2
-1 + 3 = 2
0 + 2 = 2
1 + 1 = 2
2 + 0 = 2
3 - 1 = 2
Math Packet