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Transcript

Objectives

The objective of the experiment was to synthesize an alkene product from a Wittig reagent and an aldehyde to determine whether electronic characteristics present on the para position of the aldehyde affects the formation of E or Z product. From the synthesized product, a NMR spectra will be taken and be used to identify whether the Z, E, or both products were formed. The ratio of Z to E product will then be calculated.

Theory and Principles

Conclusion

The presence of an electron withdrawing group on the aldehyde / ketone reagent leads to electrons being pulled away from the carbonyl carbon. This leads to a faster reaction and the formation of the Z alkene. The opposite holds true when there is an electron donating group.

-Hypothesis is rejected because the E to Z ratios were inaccurate for 4-nitrobenaldehyde and 4-chlorobenzaldehyde

-Products of Wittig Reactions are not very affected by the reactant but rather the ylide

Mechanisms

Explanation:What is a Wittig Reaction?

Wittig Reactions

A Wittig reaction is when an aldehyde or ketone reacts with a triphenylphosphine ylide to create an alkene and triphenylphosphine oxide byproduct.

Discussion

- Hypothesis is rejected because the data does not support hypothesis

An ylide is a molecule that contains both an atom with a positive formal charge adjacent to another atom with a negative formal charge.

Results

Why the hypothesis is rejected ?

Errors

- All of the reactants contained more E alkenes to Z alkenes

  • Instrumental Error
  • Impurities in the HNMR

Reasoning Behind Data

-The contributing factor that affects whether the product will be E isomers or Z isomers is the ylide.

- When an ylide is stabilized by other electron withdrawing groups then it will result in more E alkenes and a slower reaction

-An ylide is unstable when it does not have groups withdrawing electrons from the carbon, which results in a majority of Z alkenes and a faster reaction.

Calculations

Conversion percentage : Amount of Aldehydes fully converted into product.

= E + Z Integration / ( integration of aldehyde + E + Z Integration)

E to Z Ratio:

Amount of E alkenes in contrast to Z alkenes

= E or Z integration/ E + Z Integration

4- nitrobenzhaldehyde

E to Z ratio = 92 to 8

Conversion = 93 %

4-Chlorobenzaldehyde

E to Z Ratio = 90 to 10

Conversion = 100 %

P -tolualdehyde

E to Z ratio = 83 to 17

Conversion = 97.5 %

Hypothesis

There should be more Z alkene formed from the aldehyde containing the strongest electron withdrawing group, meaning 4-nitrobenzaldehyde should produce the most Z alkene.

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