The equation for this parabola is y = -x^2 + 36.
In the distance, an airplane is taking off. As it ascends during take-off, it makes a slanted line that cuts through the rainbow at two points. Create a table of at least four values for the function that includes two points of intersection between the airplane and the rainbow.
The airplane will cross the rainbow at (-4.9,11.99) and (6,0).
The equation of the line is...
Find the slope using
m = (y2-y1)/(x2-x1)
we plug in the intersection points.
m=(0-11.99)/(6-(-4.9))
and that will get us m=-11.99/11.9
which will equal -1
now we plug in m into the slope intercept formula
y=mx+b
y=-1x+b = y=-x+b
Now we'll have to find the y-intercept.
We use one of the point to solve for it. -> (6,0)
0=-1(6)+b So, the y-intercept is 6.
0=-6+b now plug the numbers into
+6 +6 the formula.
6=b y=-x+6
the domain and the range of -x^2+36;
range -> (-infinity,36)
domain -> (-infinity, infinity)
the domain represents the values that are possible for (x).
range represents the values that are possible for (y).
the values make mo sense because it can not be graphed.
the y and x-intercepts of f(x)=-x^2+36;
y-intercepts : (0,36)
x-intercepts : (6,0) (-6,0)
each intercept represent points where functions touch the x and y axis.
the linear function is negative because it's decreasing.
the solutions are two points ;
(6,0) and (-4.9,11.99)
these points represents where the rainbow intersects the airplane.
y={5x+4/ 3x where the first equation is true if -5<x<2 and the second equation is true if x<2.
For the red line, the segment in between the points is what you want to graph. The points should be solid. This is because it is a "less than or equal to" equation. For the blue line, the segment below the point is what you need to graph. The point should be solid for the same reason as above