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R = 62.3637
T = 20°c = 293.15°K
x
by adding 273.15 to convert into Kelvin
C = 12.011
H = 1.008
4 x (12.011) + 10 x (1.008)
=
Finding the Partial Pressure of Dry Butane:
P = P - P
250mL = the amount of water we started with
butane room water vapor
30mL = the amount of water remaining in the bottle
The temperature of water was 20°c, so the water vapor pressure is 17.5 (in torrs)
250mL - 30mL = 220mL
The pressure of the room as measured on the barometer was 746 torrs
V =
P=
220mL = the volume of butane gas collected
P = 746 - 17.5
butane
0.22L
P = 728.5
of butane gas collected
butane
x
Initial mass of lighter = 14.8805
Mass of lighter after = 14.3607
Mass of butane gas used = 14.8805 - 14.3607
G =
Mass of butane = 0.5198