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To find the efficiency of the "homemade" calorimeter we used by determining the heat given off by two different substances, a cheese puff and a marshmallow.
1. Graduated Cylinder
2. Test tube Stand (with clamp)
3. Water
4. Thermometer
5. Small stand to hold food objects
6. Cheese Puffs
7. Marshmallows
8. Insulation (soda can)
9. Rag
10. Rubber Stoppers
11. Toothpicks
12. Test Tube
Q = MCp T
When we burned the food, the glucose molecules and the oxygen molecules combusted to form carbon dioxide, water, and most importantly, energy.
This transformation from a complex molecule to a much simpler one released the stored chemical energy that was in the glucose. However, fire was required in this experiment because it takes energy to break bonds. This process also occurs in the body when we consume food.
The equation Q=MCp T helped us to determine the amount of energy that was given off by the burning food.
We used water, for which the specific heat is known, to calculate how much energy was released by the food substance via the absorption of energy into the water.
The amount of energy absorbed by the water is therefore theoretically equal to the amount of energy that was given off by the food after it was burned.
By calculating the energy that was put into the water to cause the temperature rise, we were able to convert to Calories from Joules (since 1 cal = 4.18 J and 1000 cal = 1 Cal) and divided by the amount of food substance burned to find out the Calories per gram of the substance.
Once that was complete, we compared that to the Calories per gram on the nutrition label of the food substance by dividing and then multiplying by 100 to calculate the efficiency of the calorimeter.
We calculated the efficiency of the calorimeter to see how accurately the calorimeter can determine the actual calories there are in piece of food and whether we can use the data we obtained as accurate information.
In real life, the efficiency of the calorimeter is important because if the efficiency is very low, then the data is not accurate and thus does not reflect the actual amount of calories in that particular food, which should not be distributed to the real world.
Major Errors
Effects of the Errors
The lack of even heating could lead to a lower final temperature, and thus a smaller change in temperature, which would then cause the amount of energy release from the burning marshmallow/cheese puff to look as if it lost less than it actually did, affecting the efficiency percentage. It could also show a higher final temperature, also negatively affecting the efficiency percentage.
Heat loss to the environment would also cause a lower final temperature and thus affect the percent efficiency. The heat loss could have been during the experiment, such as because of the cover/insulator we used, or because we unintentionally took time to place the marshmallows/ cheese puff under the test tube to heat the water. (This allowed some of the heat that burned the food to escape without heating the water, which would have affected the temperature.)
Theoretically, we should have had about 4.02% efficiency, however, for the marshmallows we had 10.216% efficiency and for the cheese puffs we had 24.249% efficiency. The percent efficiency was much higher for the cheese puff because we did not completely burn it.
In A Perfect World...
If we could repeat the experiment an infinite amount of times, that would decrease the amount of error that we have. Also, if none of the heat generated was lost to the surroundings, that would allow for greater accuracy. Finally, if we could have an actual calorimeter, that would make our results much more accurate.