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PE=m x a x h
PE=(.0025 kg)(9.8m/s^2)(1609m)
PE=39.42 J
Fa = -Fb
Force of Wind = -Force of Tuned Mass Damper
A 100mph gust of wind exerts a force of 3,000 newtons on the top of a 1,500ft building. What force does the tuned mass damper exert back?
PE near top = 10 calories
Fa=-Fb
6,000N=-6,000N
-6,000N
Fa=Fb
9,000N=-9,000N
-9,000N
1: Object at rest stays at rest; object in motion stays in motion
2: Acceleration is directly related to net force but indirectly related to mass (or, F=ma)
For every action, there is an equal and opposite reaction.
Force of A = -Force of B
Direct Relationship
Force = mass (kg) x acceleration (m/s^2)
[mass is the measure of an object's matter]
[acceleration is change of velocity per unit of time]
3: For every action, there is an equal and opposite reaction
What if you dropped the penny from the top of a future mile high (1609 m) skyscraper? What is its potential energy at the top?
All PE
Potential
to
Kinetic
Fa=-Fb
3,000N=-3,000N
-3,000N
All KE
This force is about 5 times the force that the earth’s gravity exerts on the average human.
What if the wind’s force doubles, to 6,000 N? Triples to 9,000 N?
PE=m x a x h
PE=.0025kg x 9.8m/s^2 x 442m
PE=10.83 J
KE=1/2mv^2
KE=(1/2)(.0025kg)(45m/s)^2
KE=2.53 J
PE near top = 2.5 calories
KE near bottom = 0.5 calories
Terminal velocity is the reason for this difference.
If you were to drop a 2.5g penny from the top of the 442 meter Sears Tower, what would be its potential energy before you dropped it? What would be its kinetic energy 2 meters from the ground? Assume its terminal velocity is 45 m/s.
KE = kinetic energy (J)
m = mass (kg)
[mass is the measure of an object's amount of matter]
PE = potential energy (J)
m = mass (kg)
[mass is the measure of an object's amount of matter]
a = acceleration (m/s^2)
[acceleration is the rate at which an object changes
its velocity]
h = height (m)
[height is the distance from the place of zero PE]
PE=m x a x h
KE=1/2mv^2
v = velocity (m/s)
[velocity is the amount of distance covered per unit of time]
1. Wind Resistance
2. Gravitational Effects
3. Force of Earthquakes
4. Energy of a Dropped Object
"If you dropped a penny from the Empire State Building, it would kill a person on impact."
As you get further from Earth's surface, the gravity you experience decreases.
Inverse Relationship
Fg = 1/d^2
Potential Energy results from the position of an object.
Kinetic Energy results from the motion of an object.
Home Insurance Building, Chicago
1885
PE=m x a x h Greater the height, greater the PE.
KE=1/2mv^2 Greater the velocity, greater the KE.
1. Wind Resistance
2. Gravitational Effects
3. Force of Earthquakes
4. Energy of a Dropped Object
Because distance is inversely related to gravity,
could a skyscraper that is built tall enough cause
a noticeable difference in the force of gravity?
Could it be tall enough to cause a person on the
top floor to age faster than a person on the bottom
floor?
Fg = force of gravity exerted on each body (N)
G=6.67 x 10^-11
[gravitational constant]
m1 & m2 = mass of two bodies (kg)
[mass is the measure of an object's matter]
Force on small building
vs. Force on tall building
d = distance between the two bodies (m)
[distance is displacement]
What is the force of gravity on a 70kg person staying on the 163rd floor of the Burj Dubai (about 830 meters)? What about the force on the same person if he or she is on the 1st floor (about 1 meter)?
The Burj Dubai weighs 498,961,607 kg, and the distance from earth's surface to its center is 6,371,000 m.
Fg=G(m1m2)/d^2
G=6.67 x 10^-11
San Francisco Earthquake, 1906
1: Object at rest stays at rest; object in motion stays in motion
F=ma
F=(136,077,711kg)(0.5 m/s^2)
F=68,038,855.5 N
Top Floor:
Fg=G(m1m2)/d^2
Fg=6.67x10^-11(70kgx(6x10^24kg))/(6,378,047^2)
Fg=688.652N
How much force would be exerted on SF's Transamerica Building in an earthquake? The building is roughly 136,077,711 kg, and during a severe earthquake, the ground can accelerate at roughly 0.5 m/s^2.
F=ma
F=(201,849,000kg)(0.5m/s^2)
F=100,924,500 N
This is more than 30,000,000 more Newtons of force than the San Francisco tower experienced. Thankfully we aren’t as likely to have earthquakes in Chicago.
The bigger the mass, the bigger the force. The larger
the acceleration, the larger the force.
F = ma
Direct Relationship
2: Acceleration is directly related to Force but indirectly related to mass (or, F=ma)
The distance between the first floor and the
top floor is about 1.5 Newtons.
This difference is the equivalent to
about 1.5 apples.
This is the same force as a 1 ton car hitting you
straight on at 168 miles per hour. (75,000 m/s).
This shows the importance of engineering a
building to withstand even the smallest vibrations.
First Floor:
Fg=G(m1m2)/d^2
Fg=6.67x10^-11(70kgx(6x10^24kg))/(6,371,001^2)
Fg=690.176 N
F = force (N)
m = mass (kg)
[mass is the measure of an object's amount of matter]
a = acceleration (m/s^2)
[acceleration is the rate at which an object changes its velocity]
3: For every action there is an equal and opposite reaction
What if a 5 mile (8047 meter) high skyscraper was built? What would be the force of gravity on a 70 kg person on the top floor opposed to the first floor (1 meter from surface)?
163rd floor:
Fg=G(m1m2)/d^2
Fg=6.67x10^-11(70kgx(6x10^24kg))/(6,371,830^2)
Fg=689.996N
What if an earthquake of the same strength stuck Chicago and the 201,849,000 kg Sears Tower? How much force would be exerted on the Sears Tower?
1st floor:Fg=G(m1m2)/d^2
Fg=6.67x10^-11(70kgx(6x10^24kg))/(6,371,001^2)
Fg=690.176 N
Acceleration
0.5 m/s^2
Gravitational force on first floor is 0.18 N greater than on the top floor.
0.18 N is roughly equal to 1/5 of an apple's weight.
The person on the first floor will age slower than the person at the top, but only by a minuscule amount.