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Gas Laws Project
DA
by
Divya Addepalle
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Updated Apr 4, 2022
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Chapters
00:00
Chapter 1
00:07
Chapter 2
00:17
Chapter 3
00:26
Chapter 4
00:29
Chapter 5
00:30
Chapter 6
00:34
Chapter 7
00:46
Chapter 8
00:48
Chapter 9
01:08
Chapter 10
01:09
Chapter 11
01:12
Chapter 12
01:18
Chapter 13
01:33
Chapter 14
01:35
Chapter 15
01:36
Chapter 16
01:45
Chapter 17
01:54
Chapter 18
01:55
Chapter 19
01:57
Chapter 20
01:59
Chapter 21
02:15
Chapter 22
02:16
Chapter 23
02:36
Chapter 24
02:37
Chapter 25
02:55
Chapter 26
02:57
Chapter 27
Audio Transcript
Auto-generated
00:01 - 00:05
So for my Gasol's project, I decided to choose scenario number two,
00:05 - 00:06
which is a hot air balloon scenario.
00:09 - 00:13
So you are a hot air balloon operator wanting to voyage across
00:13 - 00:17
the atlantic ocean without plummeting to your death in shark infested waters.
00:18 - 00:22
So what factors do I need to take into account in terms of gas laws in
00:22 - 00:27
order to make it safely across the ocean and what gas laws apply to this situation.
00:31 - 00:36
So the factors I need to take into consideration our first, the volume,
00:36 - 00:39
the size of the high air balloon can determine the volume.
00:39 - 00:42
We want a bigger hot air balloon as it contains
00:42 - 00:44
a bigger volume and can go higher in the air,
00:44 - 00:47
making our voyage across the atlantic possible.
00:48 - 00:51
We also need to take into consideration the temperature.
00:52 - 00:55
We also need a proper temperature present fueling the hot air balloon,
00:55 - 00:58
since volume and temperature are directly proportional
00:59 - 01:03
according to our gas law as one goes up. So does the other,
01:03 - 01:05
as the temperature in the hot air balloon goes up,
01:05 - 01:08
so does the volume that's allowing the balloon to go higher.
01:11 - 01:13
So what gas law does this pertain to?
01:15 - 01:17
It applies to Charles law.
01:18 - 01:23
And the explanation is that Charles law means that the set volume of an
01:23 - 01:28
object is directly proportional to the temperature of the object as one goes up.
01:28 - 01:31
So does the other, they are directly proportional.
01:37 - 01:38
So the solution.
01:39 - 01:42
The final solution to our problem is to increase the temperature adequate to
01:42 - 01:45
the volume of the balloon in order to keep it in the air.
01:47 - 01:49
The bigger the balloon, the higher can go
01:49 - 01:53
and the heat gas released from the fire to fuel fills up the balloon,
01:53 - 01:55
which makes it flow and go higher.
01:57 - 01:58
So how does this work?
02:01 - 02:03
Well, First, when he gets added to the balloon,
02:03 - 02:06
it increases the kinetic energy of the gas
02:06 - 02:08
particles causing the particles to move around.
02:09 - 02:11
And as the particles get heated up,
02:11 - 02:15
they move against the cold air surrounding them and allow the balloon to rise
02:18 - 02:23
as there's cold air both inside and outside the balloon Before it is heated up,
02:23 - 02:26
it will go the natural direction in which cold air moves, which is downward,
02:27 - 02:28
but whatever heat is added,
02:28 - 02:30
the heat particles move around in the balloon,
02:30 - 02:33
allowing the balloon to move in the director general
02:33 - 02:36
motion that the heat moves in which is upward.
02:40 - 02:43
A smaller balloon means a smaller volume and
02:43 - 02:45
flame so we cannot travel or float higher.
02:46 - 02:48
But a larger balloon means that we can have a larger
02:48 - 02:51
flame as well since the volume of the balloon has gone.
02:52 - 02:55
This means that the balloon can float up faster and travel longer.
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