Send the link below via email or IMCopy
Present to your audienceStart remote presentation
- Invited audience members will follow you as you navigate and present
- People invited to a presentation do not need a Prezi account
- This link expires 10 minutes after you close the presentation
- A maximum of 30 users can follow your presentation
- Learn more about this feature in our knowledge base article
Do you really want to delete this prezi?
Neither you, nor the coeditors you shared it with will be able to recover it again.
Make your likes visible on Facebook?
Connect your Facebook account to Prezi and let your likes appear on your timeline.
You can change this under Settings & Account at any time.
Chapter 3 Mass relationship in chemical reaction
Transcript of Chapter 3 Mass relationship in chemical reaction
Atomic mass unit (amu)
1) For atoms ---> Atomic mass (amu)
2) For molecules ---> Molecular mass (amu)
3) For formula units ---> Formula mass (amu)
In general ---> molar mass (g/mol)
1) Moles (mol) = Mass (g) / molar mass (g/mol)
2) Moles (mol) = # of particles / 6.02x 10^23
Finding % composition
of element in compound
n x molar mass of element/ molar mass of compound x 100 %
Finding Empirical and
1) Percentage (%)
2) Mass (g)
3) Moles (mol)
4) Smallest whole-number ratios
5) ---> Empirical formula (EF)
6) (Emprical mass) n = Formula mass
7) ---> Molecular formula (MF)
1) Balance the chemical equation.
2) Determine known (reactant) and unknown (product)
3) Convert known (mass) into moles.
4) Use coefficients (
) to relate the known to unknown
5) Solve for unknown (in moles)
6) Convert unknown into mass
7) Identify limiting reactant (LR) and excess reactant (ER)
8) Choose the
amount of product (based on LR) = thereotical yield
9) Calculate percent yield if given actual yield
10) Percent yield (%) = actual yield (g)/ theoretical yield (g)
Average Atomic Mass (AAM)
1) AAM= Sum of (isotopic mass x fractional abundance)
2) AAM= Sum of (isotopic mass x percentage abundance)/ 100