CONCLUSION

DESIGN COLUMN

Design column c-1 gb groundbase.

Unbraced column,short column <10.

Axial load and biaxial moment.

Mx and My was obtained from esteem,while axial load was determined from ULS calculated from the design project.

1.N/bh

2.M/bh^2

3.d/h

GROUP MEMBER

DESIGN BEAM

1. Determine total dead load, Gk

2. Determine live load, Qk

3. Design load ( ULS and SLS)

4. Determine Vmax and Mmax

5. Determine K value

6. Determine As and As'

7. Shear link test

8. Deflection test

9. Cracking test

10. Reinforcement details

**REINFORCED CONCRETE DESIGN**

INTRODUCTION

- TWO STOREY BUNGALOW

- LOCATED AT :

LOT 904, JALAN KAMPUNG KU SAYANG, MUKIM BUKIT BARU, DAERAH MELAKA TENGAH,

MELAKA BANDARAYA BERSEJARAH.

SPECIFICATION AND REFERENCES

Based on BS 8110 : 1985 Structure Use of Concrete

BS 6399 : Code of Practice for Dead and

Imposed Loads

Beam Detailing

RELATED PROBLEM

due to differencess of tributery area affect design load.

square area and circle area.

Lots of human error that can't be determined and detected.

Lots of differences between esteem and manual design calculation.

Lacks of experienced.

MUHAMAD HANIS BUANG

FARIQ AZAHA

HUD JUMITSTROWIJOYO

AHMAD NAFEK AUGUST FOUZY

AHMAD SUFIAN NUDIN

MUHAMAD ARIF ABDUL AZIZ

REAL BUNGALOW

Loading

a) Dead Loads

Dead loads for the typical area are as follows:

Unit weight of concrete 24.0 kN / m2

Finishes 0.2 kN / m2 (Cement render)

1.0 kN / m2(Homogenous/Ceramic Tiles)

Brickwall 2.6 kN / m2 (115 mm thick with 20 mm thick of plaster on both side)

Glass 0.3 kN / m2

Roof tiles 0.7 kN / m2

Battens 0.05 kN / m2

Ceiling, M&E services, duct, trusses 1.5 kN / m2

Water 9.81 kN /m3

b) Imposed/Live load

Imposed loads for particular areas shall be referred to the usage of the floor space and being taken in accordance with BS 6399 : Part 1

Bedrooms 1.5 kN / m2

Living room 1.5 kN / m2

Kitchen 2.0 kN / m2

Toilet 2.0 kN / m2

Car porch 3.0 kN / m2

Roof 0.75 kN / m2

c) Wind Loads

Wind action is not critical and negligible, notional loads govern

d) Seismic Loads

No significant seismic activity in the project area. Thus, seismic loading is not applicable.

DESIGN SLAB

for designing slab, 2 type of slab :1 way slab, 2ways slab.

for this project,design slab was a 2 ways slab.

to design the reinforcement of slab, we always need to find M in both direction.

by using shear coefficient, we can determined both moment in x and y direction.

RELATED PROBLEM

there was difference area and steel requirement in slab design when compared to esteem. This is because,lots of different value of load was placing on the slab design.

lack of experienced also causes lots of information does not meet the requirement in designing slab.

DESIGN PAD FOOTING

There are 2 type of pada footing; axial load, and moment bending which divide into 2, 1 direction and 2 direction.

We only take into consideration axial load. Same goes to Esteem software.

DESIGN ROOF

DESIGN STAIRCASE

BILL OF QUANTITIES

STRUCTURE DRAWING

3D DRAWING

SITE VISIT

Q & A session

SOLUTION

choose the most beneficial tributery area.

Carefully and guided from supervisor from experinced people.

DESIGN COLUMN

En. Mohd Nurazam Bin Husin

Penolong Jurutera JKR Daerah

Melaka Tengah

Pn. Nor Khadijah Binti Ruslan

Juruteknik Kanan JKR Melaka

En. Baharom Bin Hashim

Juruteknik Kanan JKR

Melaka

SITE VISIT

APPENDIX

Prof Dato' Dr. Ir. Wan Hamidon Wan Badaruzzaman

En. Yazmil Yatim

Mentor Vintage Engineer

VIDEO

DESIGN PAD FOOTING

Thus, we get w x L values.

SOLUTION

due to error in calculating load on slab, it produce lots of error that extremely hard to find,thus a guidance can help in designing better slab.

Beam- Hud

Slab - Fariq

Column-Ahmad

Footing- Arif

Stair- Nafek

Roof- Hanis

1) Calculate the load that are applied to the pad footing. Load from slab to beam and so on. Also calculate dead and live load.

2) Q allowable (soil investigation)

3) Find punching shear to know the effective depth . Find D first, which is D = d min + cover + diameter of bars/2

4) Take a little bit larger value for D (more safe)

5) Find the footing size. First find the depth of soil = Df - D. Next, calculate total load = (soil height x unit weight) + (concrete high, D x unit weight concrete)

6) Next, find the serviceability limit state = 1.0 Gk + 1.0 Qk. And serviceability/net allowable bearing pressure, Qnet = Area, m2.

7) Find area. Then calculate flexural reinforcement to find the reinforcement size.

x3 = (B-C)/2

P = ULS/area

M = W x (P x X3)^2/2

8) k = M/bd^2(fcu). Must k <0.156. We do not need compression steel. k > 0.156, we need compression. (cut cost)

9) find z = d (0.5 + (0.25 - k/0.9)^1/2). To prevent cracking.

10) S required = M/0.87(fy)(z)

Cut section

Side view

First floor

Ground floor

Material :

Characteristics strength of concrete, fcu

Beam and slab 30 N / mm2

Pad footing and column 30 N / mm2

Characteristics strength of reinforced, fy 460 N / mm2

Characteristics strength of links, fyv 250 N / mm2

Concrete density 24 KN / m3

Assumption :

Fire resistance 1.5 hours

Exposure condition Light

Ground floor suspended slab

Soil bearing pressure 100 KN / m2

L-shaped staircase

Design staircase as slab

Step to determine Structural Layout:

1. Understand the Architectural Drawing

- Use of Space

- Dropping

2. By 'try and error' placed the structure of:

- Beam

- Slab

- Column

Beam - placed under brickwall

- secondary beam under long span of slab

Slab - At space need for the use

column - Intersection of beam

3. Find at most severe condition at the structure

- To solve the problem, placed more structure to support the load.

1. Project Site Preparation

`

2. Project Earth Excavation Costing Tables

earth excavation volume and cost

3. Project Formwork and Concrete Costing Tables

Concrete Volume and Cost

Lean Concrete Volume and Cost

Formwork Area and Cost (Exclude Opening for RC Wall)

4. Project Reinforcement Costing Tables

5. Brickwall cost

6. Roofing cost

7. Equipment renting

Total Project Costing with Pad Foundation