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# Cell Lab

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by

Tweet## Emily Jones

on 28 November 2012#### Transcript of Cell Lab

Emily, Reema, Hailey, Karthik and Anmol Cell Size/Osmosis and Diffusion Lab Purpose Cell Size Lab Predictions and Hypothesis Mass after 5

minutes

20.6

20.21

19.44

20.51

19.97 Table Pictures of Data Questions From Handout Cell Size Lab Sources of Error Cell Size Lab Conclusions Cell Size Lab Potato Core Lab Group Experiment We predicted that the 1cm x 1cm cube would have the greatest chance of survival because it would have the greatest surface area to volume ratio. Potato Core Lab We predicted that potato in the 1.0 M solution would lose the most mass and the potato in the .8 M solution would also lose mass, but not as much as the 1.0 M solution. Group Experiment We predicted that each dialysis tube would increase in mass. The tube with the 1.0 M solution would increase the most in mass, .8 M solution would increase the second most and so on. The agar cubes, especially the cube that was supposed to be 4cm x 4cm was not cut exactly to those specifications, one side was closer to 3.5 cm in length. Potato Core Lab The cubes were slightly larger than 1cm x 1cm and the scale was not correctly zeroed before finding the mass of the potato cubes, this slightly altered the starting mass of the cubes. Group Experiment The same pipet was used to measure the unknown solutions from each beaker which could have resulted in a slightly different molar mass of the solutions. The results showed that the smallest cube absorbed the most solution, the largest cube absorbed the least solution. This shows that the extremely small size of cells allows for a large surface area to volume ratio. Potato Core Lab The results of this lab were that the potato cores that were placed in the high molar solutions (1.0 M and .8 M) lost the most mass. This shows that a solution will move from an area of high concentration to an area of low concentration. In this case, water diffused out of the potato cells because the concentration of water was higher in the potato core than in the sucrose solution. Group Experiment In the lab that we designed, the objective was to look at where the water would travel after placing the objects into water for a certain amount of time. This term is called osmosis. It had come to our attention by the end of the experiment that the water traveled into the dialysis tubes depending on the sucrose solution in each tube. We determined the unknown solutions to be A: 0.8 M, B: 1.0 M, C: 0.2 M, D: 0.6 M, and E: 0.4 M. - We are doing this lab to determine the significance of the surface area to volume ratio in cells

- The point of this lab was to observe diffusion and to determine the optimal size of cells.

- The major question being asked is: How does a decrease or increase in the size of a cell affect the cell? -We are doing this lab to observe the change in mass due to diffusion/osmosis.

- The point of this lab was to determine the change in mass in potato cores and the cause of the change in mass.

- The major question being asked is: will water diffuse into or out of a cell depending on the concentration of the solution outside of the cell? - We are doing this lab to determine the Molar Masses of five unknown solutions

-The point of the lab was to use the principles of osmosis and diffusion to find the unknown solutions

-The major question being asked is: What does the change in mass due to osmosis of an unknown solution reveal about the solution's sucrose concentration? Mass before

Water

A. 17.57

B. 18.10

C. 17.21

D. 17.82

E. 17.48 Mass after

water

20.02

20.91

18.74

20.09

19.22 Mass

change

2.45

2.81

1.33

2.27

1.74 1. At this point in the lab, which of the three "cells" do you think has the best chance of survival? Why?

-The smallest agar because it has a greatest surface area to volume ratio.

2. How many 1-cm cubes would be needed to make a 4-cm cube?

-64 1-cm cubes

3. Do the surface area and volume of a cell increase at the same rate?

-No

4. List the cubes in order of their surface area to volume ratio, from largest to smallest.

-1 cm, 4 cm and 2 cm

5. What happens to the surface area to volume ratio as a cell increases in size?

-The ratio decreases

6. What happened to the cubes as you poured the NaOH into the beaker?

-They turned pink as we poured the NaOH in the beaker

7. Do the percentages that you calculated for Table 3 change your mind about your answer to number 1?

-No, because our answer was correct and the smallest cube came out to have the biggest percentage.

8. What did you notice when you measured the width of the pink area of each cube?

-The width was small in the 4cm cube, about half of the 2cm cube, and took up the entire 1 cm cube. Molar Mass

0.8 M

1.0 M

0.2 M

0.6 M

0.4 M Group Experiment Results Cell Size Lab Potato Core Lab Group Experiment Are there any questions?

Full transcriptminutes

20.6

20.21

19.44

20.51

19.97 Table Pictures of Data Questions From Handout Cell Size Lab Sources of Error Cell Size Lab Conclusions Cell Size Lab Potato Core Lab Group Experiment We predicted that the 1cm x 1cm cube would have the greatest chance of survival because it would have the greatest surface area to volume ratio. Potato Core Lab We predicted that potato in the 1.0 M solution would lose the most mass and the potato in the .8 M solution would also lose mass, but not as much as the 1.0 M solution. Group Experiment We predicted that each dialysis tube would increase in mass. The tube with the 1.0 M solution would increase the most in mass, .8 M solution would increase the second most and so on. The agar cubes, especially the cube that was supposed to be 4cm x 4cm was not cut exactly to those specifications, one side was closer to 3.5 cm in length. Potato Core Lab The cubes were slightly larger than 1cm x 1cm and the scale was not correctly zeroed before finding the mass of the potato cubes, this slightly altered the starting mass of the cubes. Group Experiment The same pipet was used to measure the unknown solutions from each beaker which could have resulted in a slightly different molar mass of the solutions. The results showed that the smallest cube absorbed the most solution, the largest cube absorbed the least solution. This shows that the extremely small size of cells allows for a large surface area to volume ratio. Potato Core Lab The results of this lab were that the potato cores that were placed in the high molar solutions (1.0 M and .8 M) lost the most mass. This shows that a solution will move from an area of high concentration to an area of low concentration. In this case, water diffused out of the potato cells because the concentration of water was higher in the potato core than in the sucrose solution. Group Experiment In the lab that we designed, the objective was to look at where the water would travel after placing the objects into water for a certain amount of time. This term is called osmosis. It had come to our attention by the end of the experiment that the water traveled into the dialysis tubes depending on the sucrose solution in each tube. We determined the unknown solutions to be A: 0.8 M, B: 1.0 M, C: 0.2 M, D: 0.6 M, and E: 0.4 M. - We are doing this lab to determine the significance of the surface area to volume ratio in cells

- The point of this lab was to observe diffusion and to determine the optimal size of cells.

- The major question being asked is: How does a decrease or increase in the size of a cell affect the cell? -We are doing this lab to observe the change in mass due to diffusion/osmosis.

- The point of this lab was to determine the change in mass in potato cores and the cause of the change in mass.

- The major question being asked is: will water diffuse into or out of a cell depending on the concentration of the solution outside of the cell? - We are doing this lab to determine the Molar Masses of five unknown solutions

-The point of the lab was to use the principles of osmosis and diffusion to find the unknown solutions

-The major question being asked is: What does the change in mass due to osmosis of an unknown solution reveal about the solution's sucrose concentration? Mass before

Water

A. 17.57

B. 18.10

C. 17.21

D. 17.82

E. 17.48 Mass after

water

20.02

20.91

18.74

20.09

19.22 Mass

change

2.45

2.81

1.33

2.27

1.74 1. At this point in the lab, which of the three "cells" do you think has the best chance of survival? Why?

-The smallest agar because it has a greatest surface area to volume ratio.

2. How many 1-cm cubes would be needed to make a 4-cm cube?

-64 1-cm cubes

3. Do the surface area and volume of a cell increase at the same rate?

-No

4. List the cubes in order of their surface area to volume ratio, from largest to smallest.

-1 cm, 4 cm and 2 cm

5. What happens to the surface area to volume ratio as a cell increases in size?

-The ratio decreases

6. What happened to the cubes as you poured the NaOH into the beaker?

-They turned pink as we poured the NaOH in the beaker

7. Do the percentages that you calculated for Table 3 change your mind about your answer to number 1?

-No, because our answer was correct and the smallest cube came out to have the biggest percentage.

8. What did you notice when you measured the width of the pink area of each cube?

-The width was small in the 4cm cube, about half of the 2cm cube, and took up the entire 1 cm cube. Molar Mass

0.8 M

1.0 M

0.2 M

0.6 M

0.4 M Group Experiment Results Cell Size Lab Potato Core Lab Group Experiment Are there any questions?