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# Parabolas In Roller Coasters

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by

Tweet## Kelly Curry

on 7 April 2011#### Transcript of Parabolas In Roller Coasters

Roller Coasters Roller Coasters!!! The steeper the roller coaster,

the more fun it is:) Find the:

axis of symmetry

zeros

vertex

max. or min.

facts

the axis of symmetry is the x-value of the vertex while the minimum or maximum is the y-value of the vertex. The vertex is the coordinate in which the top of the porabola hits the graph.

the zeros are basically the x-intercepts. how to do it

The axis of symmetry of this roller coaster would be 2

the zeros are 7 and -4

the vertex is (2 , 8)

this porabola has a maximum becuase it opens up so the maximum

would be 8 this rolle coaster would be

really boring because the rate in which

is goes up then down is very low to the ground.. or the x-axis 25x^2+50x+100

If IaI is less than 1 then the parabola will open down

If IaI is more than 1 then the parabola will open up

to find the axis of symmetry you need to use the formula

-b/2a In this equation, 25x^2+50x+100,

25 is a

50 is b

and 100 is c

this is put in standard form

The formulated equation would turn out to be:

-50/2(25) which is -50/50 which equals 1

so the axis of symmetry for this equation is 1

since the axis of symmetry is the x-value of the vertex, you will plug in that number for all the values of x to find y x is 1 so the equation would be

25(1)^2+50(1)+100

which is 25+50+100

75+100

175

this is your y value of the vertex the y intercept will always be c

if there is no c then you know that the y intercept will be zero

in this equation the y intercept would be 100

axis of symmetry= 1

vertex= (1,175)

y intercept= 100

zeros= to find the zeros of this equation you need to factor the equation 25x^2+50x+100

which factors out to be

25(x^2+2x+4)

x^2+2x+4=0

Full transcriptthe more fun it is:) Find the:

axis of symmetry

zeros

vertex

max. or min.

facts

the axis of symmetry is the x-value of the vertex while the minimum or maximum is the y-value of the vertex. The vertex is the coordinate in which the top of the porabola hits the graph.

the zeros are basically the x-intercepts. how to do it

The axis of symmetry of this roller coaster would be 2

the zeros are 7 and -4

the vertex is (2 , 8)

this porabola has a maximum becuase it opens up so the maximum

would be 8 this rolle coaster would be

really boring because the rate in which

is goes up then down is very low to the ground.. or the x-axis 25x^2+50x+100

If IaI is less than 1 then the parabola will open down

If IaI is more than 1 then the parabola will open up

to find the axis of symmetry you need to use the formula

-b/2a In this equation, 25x^2+50x+100,

25 is a

50 is b

and 100 is c

this is put in standard form

The formulated equation would turn out to be:

-50/2(25) which is -50/50 which equals 1

so the axis of symmetry for this equation is 1

since the axis of symmetry is the x-value of the vertex, you will plug in that number for all the values of x to find y x is 1 so the equation would be

25(1)^2+50(1)+100

which is 25+50+100

75+100

175

this is your y value of the vertex the y intercept will always be c

if there is no c then you know that the y intercept will be zero

in this equation the y intercept would be 100

axis of symmetry= 1

vertex= (1,175)

y intercept= 100

zeros= to find the zeros of this equation you need to factor the equation 25x^2+50x+100

which factors out to be

25(x^2+2x+4)

x^2+2x+4=0