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Parabolas In Roller Coasters

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by

Kelly Curry

on 7 April 2011

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Transcript of Parabolas In Roller Coasters

Roller Coasters Roller Coasters!!! The steeper the roller coaster,
the more fun it is:) Find the:
axis of symmetry
zeros
vertex
max. or min.
facts
the axis of symmetry is the x-value of the vertex while the minimum or maximum is the y-value of the vertex. The vertex is the coordinate in which the top of the porabola hits the graph.
the zeros are basically the x-intercepts. how to do it
The axis of symmetry of this roller coaster would be 2
the zeros are 7 and -4
the vertex is (2 , 8)
this porabola has a maximum becuase it opens up so the maximum
would be 8 this rolle coaster would be
really boring because the rate in which
is goes up then down is very low to the ground.. or the x-axis 25x^2+50x+100
If IaI is less than 1 then the parabola will open down
If IaI is more than 1 then the parabola will open up
to find the axis of symmetry you need to use the formula
-b/2a In this equation, 25x^2+50x+100,
25 is a
50 is b
and 100 is c
this is put in standard form
The formulated equation would turn out to be:
-50/2(25) which is -50/50 which equals 1
so the axis of symmetry for this equation is 1
since the axis of symmetry is the x-value of the vertex, you will plug in that number for all the values of x to find y x is 1 so the equation would be
25(1)^2+50(1)+100
which is 25+50+100
75+100
175
this is your y value of the vertex the y intercept will always be c
if there is no c then you know that the y intercept will be zero
in this equation the y intercept would be 100
axis of symmetry= 1
vertex= (1,175)
y intercept= 100
zeros= to find the zeros of this equation you need to factor the equation 25x^2+50x+100
which factors out to be
25(x^2+2x+4)
x^2+2x+4=0
Full transcript