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In the month of September for math I learned....

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Deanna Maxwell

on 11 September 2013

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Transcript of In the month of September for math I learned....

Notes
Ideas
Ideas
Ideas
Math Work Sample
How to do variable expressions!
How to do related equations!
Problem:75/w=15

Solve Problems!
Problem:Four more than a number is 12.
Thank you!
This is what I have learned this month in math! I hope you enjoyed it! Thank you
Monthly Work Sample
What I learned in September for math....
* How to do replacement sets.
* How to do variable expressions.
*How to do related equations.
*How to translate words into expressions.
I will demonstrate one problem for each of the four things I've learned to do!
How to do a replacement set
Here is the problem:
3*(a+3)=42;{11,12,13}
The first thing we will do is replace "a" with 11!
3*(11+3)
3*(14)
Equals 42
Since it equals 42 we can say that 11 works!
Next we will replace
'a" with 12.
3*(12+3)
3*(15)
Equals 45
45=42 This does not work.
Final Answer!
So now we can say that 11 is the only number that makes this replacement set complete!
Finally we will test 13 for "a"!
3*(13+3)
3*(16)
48=42 This statement is not
true therefore 13 is not one of the replacement set numbers.
3*(11+3)
3*(14)
42=42
PEMDAS order
P-Parentheses
E-Exponents
M-Multiplication (from left to right)
D-Division (from left to right)
A- Addition (from left to right)
S-Subtraction (from left to right)

This is the correct order of PEMDAS.


We will need to remember PEMDAS for this problem so here is the order!
The problem: 12+g*(9/g) when g=3
The first step we are going to do is plug 3 for the "g". Then solve!
12+3*(9/3)
12+3*(3)
12+9
21
Our answer is 21!
Remember PEMDAS!
The problem: v-2w+12
w+5 when v=68 and w=4
So now we will plug in the numbers
for "v" and "w"!
68-2*4+12
4+5
=
Now we will remember PEMDAS to solve!
68-2*4+12=?
68-8+12
68-20
48
We have our first half of the problem!
4+5
9
We have the
other half of the problem!
Let's try
a harder one!
=
Our Answer is 5 R3
Problem:b*5=35
Problem:n+16=28
Problem: d-10=5
Inverse operation

In order to solve these problems we will
need to know inverse operation!
Here are the inverse for Multiplication,Division,Addition,and subtraction!
Inverse of add is subtract
Inverse of subtract is addition
Inverse of multiplication is division
Inverse of division is multiplication
First we will need to decide the inverse operation for division,which is multiplication.The new problem should look like this.
15*75=?
15*75=1,125.Lets check our work!
75/1,125=15! We are correct!
Let's decide which is the inverse operation of addition.
It's subtraction! 28-16=?
28-16=12.Let's check our work!
12+16=28! We are correct!


As you can see we have multiplication! The inverse is division! 35/5=?
35/5=7.Lets check our work!
7*5=35! we are correct!
The inverse operation of subtraction is addition! 10+5=?
10+5=15.Let's check our work!
15-10=5! We are correct!
Problem:The product of 8 and a number increased by 4 is 60.
Matching words and phrases to operations
Addition

Plus
more than
increased by
Sum
total
longer
older
Subtraction
minus
less than
decreased by
difference
shorter
younger

Multiplication
times
product
of
combine
equal groups
Division
quotient
separate
into equal
groups

This will be useful for our problems!
=
n
This presentation has been presented by Prezi
*How to do Replacement sets.
*How to do variable expressions.
*How to do related equations.
*How to translate words into expressions.
9
48
5R3
y
=
It is helpful to read the problem aloud
a couple of times!
You can also underline what you think is useful information!
{11}
Full transcript