Loading presentation...

Present Remotely

Send the link below via email or IM

Copy

Present to your audience

Start remote presentation

  • Invited audience members will follow you as you navigate and present
  • People invited to a presentation do not need a Prezi account
  • This link expires 10 minutes after you close the presentation
  • A maximum of 30 users can follow your presentation
  • Learn more about this feature in our knowledge base article

Do you really want to delete this prezi?

Neither you, nor the coeditors you shared it with will be able to recover it again.

DeleteCancel

Make your likes visible on Facebook?

Connect your Facebook account to Prezi and let your likes appear on your timeline.
You can change this under Settings & Account at any time.

No, thanks

Problem 1

No description
by

darenzwong chiles

on 6 October 2013

Comments (0)

Please log in to add your comment.

Report abuse

Transcript of Problem 1

Problem 1
If Michael Jordan has a vertical leap of 1.29 m, then what is his takeoff speed and his hang time (total time to move upwards to the peak and then return to the ground)?
Problem 2
A bullet leaves a rifle with a muzzle velocity of 521 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.840 m. Determine the acceleration of the bullet (assume a uniform acceleration).
Problem 3
A baseball is popped straight up into the air and has a hang-time of 6.25 s. Determine the height to which the ball rises before it reaches its peak. (Hint: the time to rise to the peak is one-half the total hang-time.)
Problem 10
With what speed in miles/hr (1 m/s = 2.23 mi/hr) must an object be thrown to reach a height of 91.5 m (equivalent to one football field)? Assume negligible air resistance.
Given:
a = -9.8 m/s^2
vf = 0 m/s
d = 1.29 m

Find:
vi = ?
t = ?
Problem 1
Solution:
for vi,
vf^2 = vi^2 +2ad
(0 m/s)^2 = vi^2 + 2(-9.8m/s^2)(1.29m)
vi^2 = 25.28 m^2/s^2
vi = 5.03 m/s
for t,
vf = vi + at
0 m/s = 5.03 m/s + (-9.8m/s^2)t
t = (5.03m/s)/(-9.8m/s^2)
t = 0.513 s
Given:
vi = 0 m/s
vf = 521 m/s
d = 0.840 m

Find:
a = ?
Problem 2
Solution:
for a,
vf^2 = vi^2 + 2ad
(521 m/s)^2 = (0 m/s)^2 + 2a(0.840 m)
a = (271441 m^2/s^2)/(1.68 m)
a = 1.62 x10^5 m/s^2

Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
The observation deck of tall skyscraper 370 m above the street. Determine the time required for a penny to free fall from the deck to the street below.
A bullet is moving at a speed of 367 m/s when it embeds into a lump of moist clay. The bullet penetrates for a distance of 0.0621 m. Determine the acceleration of the bullet while moving into the clay. (Assume a uniform acceleration.)

A stone is dropped into a deep well and is heard to hit the water 3.41 s after being dropped. Determine the depth of the well.
It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the Jaguar skidded to a stop with a constant acceleration of -3.90 m/s2, determine the speed of the Jaguar before it began to skid.
A plane has a takeoff speed of 88.3 m/s and requires 1365 m to reach that speed. Determine the acceleration of the plane and the time required to reach this speed.
A dragster accelerates to a speed of 112 m/s over a distance of 398 m. Determine the acceleration (assume uniform) of the dragster.

Problem 4
Solution:
d = vit + 0.5(at^2)
-370 m = (0 m/s )t + 0.5(-9.8m/s^2)t^2
t^2 = (-370 m)/(-4.9 m/s^2
t^2 = 75.5 s^2
t = 8.69 s
Problem 3
Solution:
Use first, vf = vi + at
0 m/s = vi + (-9.8 m/s^2)(3.13 s)
vi = 30.6 m/s
Now use, vf^2 = vi^2 + 2ad
(0 m/s)^2 = (30.6 m/s)^2 + 2(-9.8m/s^2)d
d = (-938 m/s )/(-19.6 m/s^2)
d = 47.9 m
Given:
vi = 0 m/s
d = -370 m
a = -9.8 m/s^2
Find:
t = ?
Problem 5
Solution:
vf^2 = vi^2 +2ad
(0 m/s^2) = (367 m/s)^2 + 2a(0.0621 m)
a = (-134689 m^2/s^2)/(0.1242 m)
a = -1.08 x 10^6 m/s^2
Given:
vi = 367 m/s
vf = 0 m/s
d = 0.0621 m
Find:
a = ?
Problem 6
Solution:
d = vit + 0.5a(t^2)
d = (0 m/s)(3.41 s) + 0.5(-9.8 m/s^2)(3.41 s)^2
d = 0 + 0.5(9.8 m/s^2)(11.63 s^2)
d =-57.0 m
Given:
a = -9.8 m/s^2
t = 3.41 s
vi = 0 m/s

Find:
d = ?
Given:
a = -3.90 m/s^2
vf = 0 m/s
d = 290 m
Find:
vi = ?
Problem 7
Solution:
vf^2 = vi^2 +2ad
(0 m/s)^2 = vi^2 + 2(-3.90m/s^2)(290 m)
2262 m^2/s^2 = vi^2
vi = 47.6 m/s
Given:
vi = 0 m/s
vf = 88.3 m/s
d = 1365 m
Find:
a = ?
t = ?
Problem 8
Solution:
for a, vf^22 = vi^2 +2ad
(88.3 m/s)^2 = (0 m/s)^2 + 2a(1365 m)
(2730 m)a = 7797 m^2/s^2
a = (7797 m^2/s^2)/(2730 m)
a = 2.86 m/s^2
for, t vf = vi + at
88.3 m/s^2 = 0 m/s + (2.86 m/s^2)t
t = (88.3 m/s)/(2.86m/s^2)
t = 30.8 s
Given:
vi = 0 m/s
vf = 112 m/s
d = 398 m
Find:
a = ?
Problem 9
Solution:
vf^2 = vi^2 +2ad
(112 m/s)^2 = (0 m/s)^2 + 2a(398 m)
12544 m^2/s^2= a(796 m)
a = (12544 m^2/s^2)/(796 m)
a = 15.8 m/s^2
Given:
a = -9.8 m/s^2
vf = 0 m/s
d = 91.5 m

Find:
vi = ?
t = ?

Problem 10
Solution:
First, Find speed, vf^2 = vi^2 +2ad
(0m/s)^2 = vi^2 + 2(-9.8 m/s^2)(91.5 m)
vi^2 = 1793 m^2/s^2
vi = 42.3 m/s

Now, convert from m/s to mi/hr
vi = 42.3 m/s(2.23 mi/hr)/(1 m/s)
vi =94.4 mi/hr
Full transcript