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LPH 105 W15 14.1-5
Transcript of LPH 105 W15 14.1-5
-Q = Q
If a 1.5 kg of piece of iron (450) goes from 200 - 75 C, by dropping it in a cup of water (4186), whose temperature goes form 25-75. What is the volume of water? (assume no energy loss)
We'll deal with the change internal energy in Ch 15
How much energy is required to bring .25 kg of water(4186) from 20 - 75 C?
How much heat is lost cooling 1.5 kg of iron (450) from 160 - 75 C?
How much energy is needed to bring 2.0kg of lead (130) from 25 C to a liquid state at 327 C (latent heat of fusion is 25000)
How much heat is lost bringing 1.5 kg of steam (2010) from 125 C down into water (4186) at 50 C? (latent heat of vaporization is 2,260,000 J/kg)
What mass of 100 C steam must be added to 1.00 kg of ice at 0 C to yield liquid water at 30 C? (333,000 and 2,260,000)
When a 290 g piece of iron(450) at 180 c is placed in a 95 g aluminum (900) calorimeter cup containing 250 g of glycerin at 10 C. The final temperature is observed to be 38 C. Estimate the specific heat of glycerin.
A 28 g ice(2100) cube at its melting point is dropped into an insulated cup container of liquid nitrogen. How much nitrogen evaporates if it is at its boiling pt of 77 K and has a latent heat of vaporization of 200,000 J/kg? (assume c is constant for ice and all heat goes to evaporating nitrogen)
Determine the latent heat of fusion of mercury using the following calorimeter data: 1.00 kg of solid HG(140) at its melting point of -39.0 C is placed in a 0.620 kg aluminum(900) calorimeter with 0.400 kg of water(4186) at 12.80 C; the resulting equilibrium temperature is 5.06 C.
What is the final temperature if a 250 g block of lead(130) initially at 200 C is dropped into a 150 g aluminum(900) cup containing 750 g of water(4186) initially at 10 C?
Heat flow rates
Plug and chug, I'll give all but 1 term and you find it.
"Can we go over convection conduction and radiation. "
"Can we discuss what latent heats means please?"
"I'm struggling with the best way to set up problems involving latent heat. "
"Can you do the last problem on quiz"
"Knowing the specific heat of water is 4186 J/kg C how much heat would be needed to raise 20 kg of water from 10 degrees to 90 degrees? (answer should look like 5800 kJ)"
"In example 14-5, why can you set all the values equal to zero when you're calculating an unknown specific heat?