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Electrical and Computer FE Exam - Engineering Sciences

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Aaron Craven

on 5 November 2014

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Transcript of Electrical and Computer FE Exam - Engineering Sciences

The Exam
FE Chemical
FE Civil
FE Electrical and Computer
FE Environmental
FE Industrial
FE Mechanical
FE Other Disciplines
Work,
Energy,
Power,
Heat

Inductance
Measured in henries (H)
H = (m^2*kg)/C^2
Opposes change in current
Looks like short circuit as frequency >> 0 Hz
looks like open circuit as frequency >> ∞ Hz
Work on a Charge in Electric Field
General FE Exam Info
Calculator Policy...


Statistics..........


Other Info..........

Charge, Energy, Current, Voltage, Power
Electrical and computer Fe Exam
-Engineering Sciences -

By:
Aaron Craven
Irina Tyx

Electrical and Computer
1. Mathematics
2. Probability and Statistics
3. Ethics and Professional Practice
4. Engineering Economics
5. Properties of Electrical Materials
6. Engineering Sciences
7. Circuit Analysis (DC and AC Steady State)
8. Linear Systems
9. Signal Processing
10. Electronics
11. Power
12. Electromagnetics
13. Control Systems
14. Communications
15. Computer Networks
16. Digital Systems
17. Computer Systems
18. Software Development

Engineering Sciences
6-9 Questions
A. Work, energy, power, heat
B. Charge, energy, current,
voltage, power
C. Forces (e.g., between charges,
on conductors)
D. Work done in moving a charge in an
electric field (relationship between
voltage and work)
E. Capacitance
F. Inductance

Forces
The work done by an external agent in moving a charge Q in an electric field from point p1 to point p2 is:
Capacitance: Unit [F]

Casio
fx-115 MS
fx-115 MS Plus
fx-115 MS SR
fx-115 ES
fx-115 ES Plus
Hewlett Packard
Texas Instruments
HP 33s
HP 35s
TI-30Xa
TI-30Xa SOLAR
TI-30Xa SE
TI-30XS Multiview
TI-30X IIB
TI-30X IIS
TI-36X II
TI-36X SOLAR
TI-36X Pro
We Recommend
TI-36X Pro
Familiar Interface
Great Reviews (4.7 out of 5) on Amazon with 1440 ratings
Costs $18.97
Angle Conversions
Vectors and Matrices
Simultaneous Equation Solver
Time:
6hr appointment
5hr 20min for exam
Questions:
110 Multiple Choice
2min 54sec per Question
WDTM:
Pass Rate:
82% of First-Time Takers for Electrical and Computer Exam
Results:
Results in 7-10 Days
Pass or Fail
Ambiguous Passing Score
Diagnostic Report if you Fail
During The Exam
So What's Next?
Charge
Energy
Current
Voltage
Power
Sample Problem
Fundamental property of subatomic particles
Electron (-1.6x10^-19 Coulombs)
Proton (+1.6x10^-19 Coulombs)
Conservation of charge
Measured in Joules
Not to be confused with work
Force F exerted E joules of energy on mass M which resulted in W joules of work done on the mass
Current is the movement of charge
Opposite direction of electron flow
Defined as charge per time
SI units coulombs/second (ampere)
i(t) = dq(t)/dt

I = dQ/dt

J
= p
v
Measured in watts
Energy per time
W = J/s = N*m/s = kg*m^2/s^3
P = IV
Measured in volts
Strength of electric field
Difference in electric potential between two points
Work required to move 1 coulomb from A to B
V = IR = P/I
Q. A current of 5A flows through a wire with a diameter of 3mm. What is the average number of electrons per second that passes through any given cross sectional point along the wire?
A. 8.0 x 10^19
B. 3.1 x 10^-19
C. 1.6 x 10^19
D. 3.1 x 10^19
1 A = 1 C/s (def)
5 A = 5 C/s

1 e = 1.6x10^-19 C (def)

5 C/s x 1/(1.6x10^-19) e/C
=
3.1x10^19
electrons/second

Answer is D.

Wire diameter is irrelevant.
Sample Problem
What is the work required to move a charge of +5 C a distance of 8 m in a uniform electric field of 100 V/m?
A. -800 J
B. 0 J
C. -4000 J
D. 4000 J
Inductance Equations
Sample Problem
What is the equivalent inductance of the circuit below?
A. 5 H
B. 20 H
C. 23.75 H
D. 25 H
L4 and L3 are in series with L2 and L1 which are in parallel.

Leq = L4 + L3 + L2//L1

= 15 + 5 + (10)(10)/(10 + 10)
= 20 + 100/20
= 20 + 5
=
25 H

Answer is D.
5 hours, 20 minutes to complete

raise hand for more
reusable booklets

scheduled break.......

unscheduled breaks....


after submitting ~55 Q's
25 minutes
may take fewer minutes, but no time incentive
may leave the building
return on time!
clock will automatically resume
may take anytime
amount of time will be deducted from testing time
access to personal items
beverages, food, and items on Comfort Aid List
EIT (Engineer in Training)
Work for at least 4 years
Take the P.E. exam
managerial positions
higher salary
new job opportunities/responsibilities
bid for gov't contracts
own a firm
consult
offer expert witness testimony
stamp and seal designs
Work
defined as "transfer of energy"
physics says, "work is done on object when you transfer energy to that object"
if one object transfers (gives) energy to a 2nd object, then the 1st object does work on the 2nd object

W = Fxd
Units: N*m, or Joules
Energy
defined as capacity for doing work
Kinetic Energy = energy of motion
Potential Energy = stored energy
Forms
Solar radiation
infrared, radio, UV, etc
Atomic/Nuclear Energy
fission: neutron splits atom's nucleus into smaller pieces
fusion: two nuclei joined together under millions of degrees of heat
Electrical Energy
generation/use of electric power over period of time
kWH, GWh
Chemical Energy
potential energy related to breaking/forming of chemical bonds
Mechanical Energy
Heat Energy

Kinetic: Ek = 1/2*m*v^2
Potential: U = 1/2 *k*x^2
Units: N*m or Joules
Power
Work done in a unit of time
measure of how quickly work can be done
Unit
SI: Watt = 1 Joule/1 second
English: 1 HP = 735.7 W
Example:
if we are using 1 kW of power, a kWh of energy will last one hour
Heat
heat is a form of energy, or thermal energy
heat energy is transferred as a result of temperature differences
Heat flow
Watt = 1 J/s of heat flow
Sample Problem
A 3500 kg car traveling at 65km/h skids and hits a wall 3 seconds later. The coefficient of friction between the tires and the road is 0.60.

Assuming that the speed of the car when it hits the wall is 0.20 m/s, what energy must the bumper absorb in order to prevent damage to the car?

(A) 70 J
(B) 140 J
(C) 220 J
(D) 360 kJ
Solution
Use the kinetic energy equation

Ek = 1/2 * m * v^2
= (1/2)(3500 kg)(0.2 m/s)^2
= 70 J

Answer is (A).


Force on test charge Q in electric field E:

F = QE

Force experienced by point charge 2 (Q2) in an electric field E, created by point charge 1 (Q1):

Sample Problem
Solution!
represents the ability to store charge
the greater the capacitance, the greater the charge stored


Capacitance of two parallel plates of equal area A, separated by distance d. Where ϵ is the permittivity of medium separating the plates


Current in a capacitor
can change instantaneously

Voltage
cannot change instantaneously
will change as the capacitor integrates the current to produce a voltage that opposes the change


Total energy (in J) stored in capacitor

Capacitors in Series:
like resistors in parallel
Cs = 1 / (1/C1 + 1/C2 +...+ 1/Cn)

Capacitors in Parallel:
like resistors in series
Cp = C1+C2+...+Cn
RC Transient Circuits
time constant
τ = RC
time it takes voltage to reach 63.3% of its steady state value
in general, transient variables will have reached their steady-state values after 5 time constants (99.3% of steady-state value)



Sample Problem
What are the voltage Vx and current Ix values through the 5Ω resistor in the center leg after a long time?

(A) 2V; 1A
(B) 2V; 3A
(C) 5V; 1A
(D) 5V; 20A

Solution!


after t=5τ, the capacitor acts like an open circuit.

Using Ohm's Law for Ix, the answer is C (5V; 1A)
Congratulations, you passed!
Full transcript