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The Tourist's Dilemma

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by

Amanda Fernandez

on 25 February 2015

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Transcript of The Tourist's Dilemma

ConclusionI
PLATFORMS
Social
SOCIAL
SEO
CMS
Problem
Work
Postcards
Conclusion
Period 06
02/24/15
.
.
Work:
Equations
I sell 3 manatee postcards and 1 alligator for as much as 2 Florida panther postcards. I also sell 1 manatee postcard, 2 alligator postcards and 3 Florida panther postcards for $25; and all the postcards are sold for a whole number of dollars.
3m+a=2p
m+2a+3p=$25
M= the price of manatee postcards
A= the price of alligator postcards
P= the price of Florida Panther postcards
3m+a=2p
-2p -2p
3m+a-2p=0
-2(3m+a-2p=0)
-6m-2a+4p=0
+m+2a+3p=25
-5m+7p= 25
-7p -7p
-5m= 25-7p
-5 -5
m= -5+7/5p

m= -5+7/5p
m= -5+7/5(5)
m= -5+35/5
m= -5+7
m= 2

m+2a+3p = 25
(2)+2a+3(15) = 25
2a+17 = 25
-17 -17
2a = 8
2 2
a = 4
Postcards
Algebra
The Tourist's Dilemma
By: Amanda Fernandez
David Paez
Postcards
Problem Statement
P must be a multiple of 5.
P>O so M>0
P<10 so 1m+2a+3p<25
So P=5
$2
$5
$4
Conclusion
First start off by subtracting 2p in attempts to get the equation to one side.

Once everything is over multiply it by -2, so it can eliminate the 2a in the other equation.


The equation is established so attempt to get one variable to the other side by subtracting by 7p
Now that we discovered that P has to be 5, we input into our equation.
35/5 = 7 therefore making the last operation
-5+7
We discover the price of manatee postcards.
Finally, input these numbers into one of the equations to find a.
Combine like terms
Subtract by 17
Divide by 2

And you end up with the last variable!
Conclusively, we figured out the price of each postcard by using the systems of equations: 3+a=2p and m+2a+3p=$25. We discovered that manatee postcards cost $2, alligator postcards cost $4, and Florida panther postcards cost $5!
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