Loading presentation...

Present Remotely

Send the link below via email or IM

Copy

Present to your audience

Start remote presentation

  • Invited audience members will follow you as you navigate and present
  • People invited to a presentation do not need a Prezi account
  • This link expires 10 minutes after you close the presentation
  • A maximum of 30 users can follow your presentation
  • Learn more about this feature in our knowledge base article

Do you really want to delete this prezi?

Neither you, nor the coeditors you shared it with will be able to recover it again.

DeleteCancel

Make your likes visible on Facebook?

Connect your Facebook account to Prezi and let your likes appear on your timeline.
You can change this under Settings & Account at any time.

No, thanks

Copy of A Semi-Detailed Lesson Plan

No description
by

Erin Quinn

on 12 March 2013

Comments (0)

Please log in to add your comment.

Report abuse

Transcript of Copy of A Semi-Detailed Lesson Plan

At the end of the session,
the students are expected to: a. Differentiate the reciprocal identities and quotient identities of trigonometric function values, and A Semi-Detailed Lesson
with Technology Integration in MATH IV Berico, Joimari C.
Valles, Clarisse Anne C. Learning Objectives b. Solve the reciprocal identities and quotient
identities involving the six trigonometric functions. Subject Matter * Topic: Reciprocal Identities and Quotient Identities * Reference: Advance Algebra, Trigonometry and Statistics * Author: Soledad, Jose-Dilao et. al., pgs. 195-200 * Materials: Interactive Media Review * What is the domain of the function sine? cosine? tangent? * What is the range of the function sine? cosine? tangent? * What is the Y-intercept of the function sine? cosine? tangent? * What are the relationships among sine, cosine and tangent? Motivation Discussion r y x x r y where: cos θ sin θ 1 Therefore: * cos θ = x * sin θ = y
* tan θ = __ y x * csc θ = __ r y * sec θ = __ r x * cot θ = __ x y , x ≠ 0 , x ≠ 0 , y ≠ 0 , y ≠ 0 Furthermore: From the given equations, note that: * csc θ = * sec θ =
* tan θ = r x y x 1 y 1 sin θ 1 x r 1 cos θ cot θ x y r y = = = 1 = 1 = 1 = 1 Hence we have the following reciprocal identities: * csc θ = sin θ 1 * sec θ = cos θ 1
* tan θ = cot θ 1 or or or sin θ = 1 csc θ cos θ = 1 sec θ cot θ =
tan θ 1 or or or sin θ • csc θ = cos θ • sec θ = tan θ • cot θ = 1 1 1 Also from the definition we have, tan θ = y x = y r x r = sin θ cos θ , cos θ ≠ 0 And since tangent and cotangent are reciprocal functions, we have, cot θ = cos θ sin θ , sin θ ≠ 0 We therefore have the following Quotient Identities: tan θ = sin θ cos θ cos θ ≠ 0 , cot θ = cos θ sin θ , sin θ ≠ 0 Ex. 1. sin θ • sec θ sin θ • cos θ 1 = sin θ cos θ = tan θ Ex. 2. csc θ • cos θ • cos θ 1 = sin θ cos θ = cot θ sin θ Ex. 3. csc θ • tan θ = = = sec θ sec θ csc θ tan θ tan θ 1 cos θ 1 sin θ sin θ cos θ tan θ = tan θ = tan θ = = Simplify the following: sec θ csc θ 1. 2. 3. sin θ sec θ • csc θ tan θ ÷ sin θ sec θ 4. 5. csc θ • cos θ Directions: Find a partner and solve the
following in a one whole sheet of paper. sec θ cot θ ÷ 1. 2. sec θ csc θ • 3. tan θ csc θ • Reinforcement Read about the Pythagorean Identities. Assignment: Evaluation BYE!
Full transcript