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# Relative motion of a swimmer in a river

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## Richard Datwyler

on 2 July 2015

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#### Transcript of Relative motion of a swimmer in a river

y = 0
0
y = 45
v = .6 m/s
s
10
0
v = .5 m/s
r
V
s
s
g
g
r
r
x
x
x
V

s
s
g
g
r
r
y
y
y
V
V
+
=
=
V
V
+
y = 0
0
y = 45
v = .6 m/s
s
10
0
v = .5 m/s
r
V = .6 cos(10) =.59
V = .6 sin(10) =.1
x
y
V = .5

V = 0
x
y
-.1
.5
.4
+ =
.59
0
.59
+ =
v = .4
v =.59
y = 0
y = 45
0
x
y
x = 0
x = ?
0
t=?
A swimmer is capable of swimming 0.6 m/s in still water. If she aims her body at an angle of 10 degrees up stream across a 45 m wide river whose current is 0.50 m/s how far downstream will she land? How long will it take her to reach the other side?
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