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# 6°____Kevin,Zihao

Exponential and logarithmic functions

by

Tweet## kevin zhang

on 13 May 2013#### Transcript of 6°____Kevin,Zihao

Zihao Li

Kevin Zhang

6 period Introduction Kevin Zhang Key Words Video Time Example 1

Solving for base is same Example 2 Example 3

Exponentiate each side using base Example 4

Use logarithm Example 5 Zihao Li Brother Log Product Property Quotient Property Power Property Inverse rule of logs Inverse rule of

exponentials Property of equality Solve for x Dropping the base Property of equality Solve for x Inverse rule of

exponential Solve for x Take logarithm Inverse rule of logs Quotient Property Solve for x Solve for extraneous solution Product Property Inverse rule of exponential Subtract both side by 36 Solve for x Check for solution -9 3 -36 -12 3x -12x -36 x 3 x -12 x 2 log (2x-6)=log (6x+7) 5 5 2x-6=6x+7 -4x=13 4x=-13 x=- _ 13 4 27 =9 x 2x+3 3 =3 3x 2(2x+3) 3x=4x+6 -x=6 x=-6 log (5x-3)=2 7 7 =7 2 log (5x-3) 7 5x-3=49 5x=52 x= _ 52 5 3 =28 x log 3 =log 28 3 3 x=log 28 3 x= _ log28 log3 x=3.033 x log x+log (x-9)=2 6 6 log (x -9x)=2 6 2 6 =6 log (x -9x) 6 2 2 x -9x=36 2 x -9x-36=0 2 (x-12)(x+3)=0 x=-3 or 12 log (-3) and log (-3-9) are not defined, 12 is the solution. 6 6 log mn=log m+log n b b log =log m-log n _ m n b b log m =n(log m) b n b log b =x b x b =x log x b Math Time Exponential and Logarithmic Functions END

Full transcriptKevin Zhang

6 period Introduction Kevin Zhang Key Words Video Time Example 1

Solving for base is same Example 2 Example 3

Exponentiate each side using base Example 4

Use logarithm Example 5 Zihao Li Brother Log Product Property Quotient Property Power Property Inverse rule of logs Inverse rule of

exponentials Property of equality Solve for x Dropping the base Property of equality Solve for x Inverse rule of

exponential Solve for x Take logarithm Inverse rule of logs Quotient Property Solve for x Solve for extraneous solution Product Property Inverse rule of exponential Subtract both side by 36 Solve for x Check for solution -9 3 -36 -12 3x -12x -36 x 3 x -12 x 2 log (2x-6)=log (6x+7) 5 5 2x-6=6x+7 -4x=13 4x=-13 x=- _ 13 4 27 =9 x 2x+3 3 =3 3x 2(2x+3) 3x=4x+6 -x=6 x=-6 log (5x-3)=2 7 7 =7 2 log (5x-3) 7 5x-3=49 5x=52 x= _ 52 5 3 =28 x log 3 =log 28 3 3 x=log 28 3 x= _ log28 log3 x=3.033 x log x+log (x-9)=2 6 6 log (x -9x)=2 6 2 6 =6 log (x -9x) 6 2 2 x -9x=36 2 x -9x-36=0 2 (x-12)(x+3)=0 x=-3 or 12 log (-3) and log (-3-9) are not defined, 12 is the solution. 6 6 log mn=log m+log n b b log =log m-log n _ m n b b log m =n(log m) b n b log b =x b x b =x log x b Math Time Exponential and Logarithmic Functions END