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# Assignment 02.06 Module Two Activity

Geometry (Flvs)

by

Tweet## Valentino G

on 29 November 2014#### Transcript of Assignment 02.06 Module Two Activity

Step 1

Valentino G.

Assignment 02.06 Module Two Activity

11/28/14

Mrs. Brooks

The Last Step

Step 2

D = (16 , 0)

E = (8 , 0)

F= (16 , 6)

It's translated with the rule (x + 10 , y + 3)

They're Congruent!

Here I'm giving proof of congruence using the distance formula

From the picture we can imply that

Line AB = Line DE

Line BC = Line EF

Line CA = Line FD

ABC similar to DEF

A' = (2 , - 3)

B' = (-6 , - 3)

C' = (-6, 3)

It's reflected over the y - axis

From the following picture we can conclude that Line AB & Line A'B' show congruence. I proved it using Angle side angle.

It's congruent.

If we want to see if AB, BC, & A'B' & B'C' form right angles in their triangles I have to use the slope formula. I already acknowledged that the slope of B'C' is 1 number & as well the slope of BC is the reciprocal of the number with also including the slope of A'B' is 1 number & line ab's slope is the reciprocal of that number. You realize that both of the triangles include right angles. This means that they are congruent.

AB's slope is 0/8

A'B' has the following slope 0 / - 8 that's flipped to get rid of the - symbol & that means it results with 8 / 0

8 / 0 is the reciprocal of 0 / 8

BC is 0 / 6

BC is 6 / 0 which means it's the reciprocal of 0 / 6

Now we realized that AB & BC on the default triangle & A'B' & B'C' on the new triangle both form right angles & means that it's congruent. Following that I prove the first angle being congruent using angle side angle

Side Note :

One thing that I noticed is that when I used a program like Geogebra I realized that's the perfect way to come up with accurate results & this is actually recommended in lesson 02.06

The last thing is basically proving that the last angle is congruent. I'm going to be using A & A'. This is going to be proved with GeoGebra & the angle setting & inform you on how many degrees the angles measures.

As you notice, the following 2 angles are similar because they both measure up to 36.87 degrees.

Rotated 180 degrees

This proves that AB & BC & A'B' & B'C' form right angles on their triangles. It means that their congruent.

Lastly this proves that AB & A'B' are similar & congruent & also BC & B'C'.

They're congruent!

Reflection Questions for 02.06

1. All I did was basically count ten spaces to the right & 3 spaces that's up from each of the 3 default points & insert a point there to make a new triangle. With this course, this particular rule is stated as x + 10, y + 3. This means you can apply or use this rule to come up or make brand new coordinates without having to use a grid. For example if we use let's say point a & our default triangle, point a's coordinates are 6, -3, use addition for adding the numbers 10 to 6 & 3 to ÈÈ [ÝHÛÛYH\Ú]HÛÛܙ[]\ÈÈH]ÈÚ[] ÜÈM] ÜÈHY][Ûܜ\Üۙ[ÈÚ[[ÛÈÙH]HÈÈHØ[YH[ÈÚ]HÝ\Ú[È\ÈÙ[ÛÈ[ÝH]HH[]ÈX[ÛH] ÜÈÚ[Z[\ÈHY][ÙHØ[ݙH]Z\Ú[Z[\\Ú[ÈH\Ý[ÙHܛ][KBBB\ÚXØ[HÝ]HHX[ÛHNYܙY\È Y\Ú[È][ÝHÝXÙH]]ÛÙ\ÈÛØÚÝÚ\ÙKBBBBBBˈHÚÜÙHHY][X[ÛH ]YXÝYXܛÜÜÈHH^\ˈH[XYHۙ]È]]HÈÚ[ÈYÈYXÝXܛÜÜÈH[HXZ[HXØ]\ÙHوHXÝ]H[XYÙH] ÜÈۈHÝ\ÚYHX]ÚYHY][\ÝKH[]ÈX[ÛHØ\Èݙ[Ú[Z[\ÈHY][

Full transcriptValentino G.

Assignment 02.06 Module Two Activity

11/28/14

Mrs. Brooks

The Last Step

Step 2

D = (16 , 0)

E = (8 , 0)

F= (16 , 6)

It's translated with the rule (x + 10 , y + 3)

They're Congruent!

Here I'm giving proof of congruence using the distance formula

From the picture we can imply that

Line AB = Line DE

Line BC = Line EF

Line CA = Line FD

ABC similar to DEF

A' = (2 , - 3)

B' = (-6 , - 3)

C' = (-6, 3)

It's reflected over the y - axis

From the following picture we can conclude that Line AB & Line A'B' show congruence. I proved it using Angle side angle.

It's congruent.

If we want to see if AB, BC, & A'B' & B'C' form right angles in their triangles I have to use the slope formula. I already acknowledged that the slope of B'C' is 1 number & as well the slope of BC is the reciprocal of the number with also including the slope of A'B' is 1 number & line ab's slope is the reciprocal of that number. You realize that both of the triangles include right angles. This means that they are congruent.

AB's slope is 0/8

A'B' has the following slope 0 / - 8 that's flipped to get rid of the - symbol & that means it results with 8 / 0

8 / 0 is the reciprocal of 0 / 8

BC is 0 / 6

BC is 6 / 0 which means it's the reciprocal of 0 / 6

Now we realized that AB & BC on the default triangle & A'B' & B'C' on the new triangle both form right angles & means that it's congruent. Following that I prove the first angle being congruent using angle side angle

Side Note :

One thing that I noticed is that when I used a program like Geogebra I realized that's the perfect way to come up with accurate results & this is actually recommended in lesson 02.06

The last thing is basically proving that the last angle is congruent. I'm going to be using A & A'. This is going to be proved with GeoGebra & the angle setting & inform you on how many degrees the angles measures.

As you notice, the following 2 angles are similar because they both measure up to 36.87 degrees.

Rotated 180 degrees

This proves that AB & BC & A'B' & B'C' form right angles on their triangles. It means that their congruent.

Lastly this proves that AB & A'B' are similar & congruent & also BC & B'C'.

They're congruent!

Reflection Questions for 02.06

1. All I did was basically count ten spaces to the right & 3 spaces that's up from each of the 3 default points & insert a point there to make a new triangle. With this course, this particular rule is stated as x + 10, y + 3. This means you can apply or use this rule to come up or make brand new coordinates without having to use a grid. For example if we use let's say point a & our default triangle, point a's coordinates are 6, -3, use addition for adding the numbers 10 to 6 & 3 to ÈÈ [ÝHÛÛYH\Ú]HÛÛܙ[]\ÈÈH]ÈÚ[] ÜÈM] ÜÈHY][Ûܜ\Üۙ[ÈÚ[[ÛÈÙH]HÈÈHØ[YH[ÈÚ]HÝ\Ú[È\ÈÙ[ÛÈ[ÝH]HH[]ÈX[ÛH] ÜÈÚ[Z[\ÈHY][ÙHØ[ݙH]Z\Ú[Z[\\Ú[ÈH\Ý[ÙHܛ][KBBB\ÚXØ[HÝ]HHX[ÛHNYܙY\È Y\Ú[È][ÝHÝXÙH]]ÛÙ\ÈÛØÚÝÚ\ÙKBBBBBBˈHÚÜÙHHY][X[ÛH ]YXÝYXܛÜÜÈHH^\ˈH[XYHۙ]È]]HÈÚ[ÈYÈYXÝXܛÜÜÈH[HXZ[HXØ]\ÙHوHXÝ]H[XYÙH] ÜÈۈHÝ\ÚYHX]ÚYHY][\ÝKH[]ÈX[ÛHØ\Èݙ[Ú[Z[\ÈHY][