### Present Remotely

Send the link below via email or IM

CopyPresent to your audience

Start remote presentation- Invited audience members
**will follow you**as you navigate and present - People invited to a presentation
**do not need a Prezi account** - This link expires
**10 minutes**after you close the presentation - A maximum of
**30 users**can follow your presentation - Learn more about this feature in our knowledge base article

Do you really want to delete this prezi?

Neither you, nor the coeditors you shared it with will be able to recover it again.

### Make your likes visible on Facebook?

Connect your Facebook account to Prezi and let your likes appear on your timeline.

You can change this under Settings & Account at any time.

# Understanding Stoichiometry

What is Stoichiometry and how do you do it

by

Tweet## Shyon Wallace

on 20 May 2011#### Transcript of Understanding Stoichiometry

Stoichiometry By: Shyon Wallace Stoichiometry deals with the relationship between combined elements or compounds involved in chemical reactions. What is Stoichomertry so basicly stoichiometry was thought up to basicly make chemistry more simple How you may ask? Well like this ok lets say you have 45 grams of Water (H O) and you want to find out how many grams of Oxygen (O )could be formed from it 2 2 So First Step: read the question and understand what it is that you are trying to find. Second Step: write what you found in the problem So now that you have that you can know move onto the next step third Step: start on the rest of the equation you should have writen down from the problem that you have 45 grams of H O and you are trying to find O from that.

so after that you should start on your equation 2 2 Which is this: Grams of

A molar

mass Moles of

A mole ratio=

Coefficients Mole of

B molar

mass Grams of

B Stoichiometry Flow Chart First is: Second is: Third is: and Forth is: example: 45g H O 1mol H O 17.99g H O 2mol O 2mol H O 31.98g O 1mol O 79.99g O * * * = but first you must first understand the Stoichiometry Flow Chart so your first step in ur equation should look like the you should have started out with this step right here Equation Now that you know that we can know move on through the rest of the equation 2 2 2 2 2 2 2 2 first you must start with this the top is how many moles it is

so H O by itself it has 1 mole and thats what you put the bottom is how many grams there are in 1 thing of H O How would you find that? You may ask, well like this: By using the Periodic Table you can find the amount of grams there are in H O so you look for both H and O and you take the # at the top of each one so you take H : which is 1.00

but notice the 2 in H O that means there is two Hs which means you have to times them together

so you should still get 1.00

next take O: which is 15.99

and you add both H and O together an it should look like this 2 2 2 2 Ok next is this the top is how many moles of O there is

the 2 comes from the little 2 on the side of O the bottom is how many moles of H O there is

ones again the 2 comes from the little 2 the next thing is this the top is how many grams there is in O ones again you go back to this and u go an look for the # at the top of O so take O : which is 15.00

an notice the 2 in O again

means you have two Os and you have to times them together

and you should get this the bottoms is how many moles you have

so O by itself has 1 mole so you put that 2 2 2 2 2 2 2 2 2 Now that you have all that you can now start to sovle the Equation so you take 45g H O and divid it by 17.99g of H O the, then the 2s in the next part cancel each other out, then times what you got by 31.98g O , then finally you get your solution which is 2 2 2 That is your Answer in the end you should get 79.99 grams of Oxygen Well Thats The End I Hope That This Helps You Understand Stoichiometry Peace Out

Full transcriptso after that you should start on your equation 2 2 Which is this: Grams of

A molar

mass Moles of

A mole ratio=

Coefficients Mole of

B molar

mass Grams of

B Stoichiometry Flow Chart First is: Second is: Third is: and Forth is: example: 45g H O 1mol H O 17.99g H O 2mol O 2mol H O 31.98g O 1mol O 79.99g O * * * = but first you must first understand the Stoichiometry Flow Chart so your first step in ur equation should look like the you should have started out with this step right here Equation Now that you know that we can know move on through the rest of the equation 2 2 2 2 2 2 2 2 first you must start with this the top is how many moles it is

so H O by itself it has 1 mole and thats what you put the bottom is how many grams there are in 1 thing of H O How would you find that? You may ask, well like this: By using the Periodic Table you can find the amount of grams there are in H O so you look for both H and O and you take the # at the top of each one so you take H : which is 1.00

but notice the 2 in H O that means there is two Hs which means you have to times them together

so you should still get 1.00

next take O: which is 15.99

and you add both H and O together an it should look like this 2 2 2 2 Ok next is this the top is how many moles of O there is

the 2 comes from the little 2 on the side of O the bottom is how many moles of H O there is

ones again the 2 comes from the little 2 the next thing is this the top is how many grams there is in O ones again you go back to this and u go an look for the # at the top of O so take O : which is 15.00

an notice the 2 in O again

means you have two Os and you have to times them together

and you should get this the bottoms is how many moles you have

so O by itself has 1 mole so you put that 2 2 2 2 2 2 2 2 2 Now that you have all that you can now start to sovle the Equation so you take 45g H O and divid it by 17.99g of H O the, then the 2s in the next part cancel each other out, then times what you got by 31.98g O , then finally you get your solution which is 2 2 2 That is your Answer in the end you should get 79.99 grams of Oxygen Well Thats The End I Hope That This Helps You Understand Stoichiometry Peace Out