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Physics Goes To The Movies! (2 Fast 2 Furious)
Transcript of Physics Goes To The Movies! (2 Fast 2 Furious)
The car's speed at the ramp can be calculated.
First, the distance
the director gives
us from the shore to
the boat is:
Can this 1969 Camaro really jump this distance to a boat?
Angle of the Ramp?
The way we found the angle is we used an awesome
over the wide
Approx. 17 degrees
In this video below we see the two main characters Brian and Roman attempt to catch up to a yacht in which they jump off a ramp with their car to land on it
This is the distance which the director gives us. Now using what we know is this distance
(When compared to the car's speed).
2 Fast 2 furious
Question is.... IS IT POSSIBLE!?
Physics Goes To The Movies!
This movie scene contains incorrect physics!
With a car traveling at 59.2m/s it would go
In the scene the movie shows it jump a mere
30m which is off by 170m! That's quite a difference.
All data was collected from the YouTube clip and 1 Wikipedia page regarding the 1969 Camaro
bY: nIKOLA mILENOVIC / cARSON wHITLOCK / rAVEEL Tejani
Velocity 39.786 m/s
Velocity 52.7508 m/s
Time between these two is The time between these two
6 seconds 3 seconds
So What Do We Know?
Initial velocity : 59.18m/s
Distance : 30.706m
Angle : 17 degrees
Time : 3.53s
*Neglecting Air Resistance
Is This Jump Realistic?
We will use the car's initial speed, the angle of the jump and the time to calculate
We can simplify these calculations:
- We will find
(velocity of x-direction)
and multiply it by the
of the jump
- With this we will find the
Vf = Vi + a(t) Vf = Vi + a(t)
52.7 = 39.7 + a(6) Vf = 52.7 + 2.16(3)
a = 2.1608m/s^2
Vf = 59.1824m/s
The car is launched at:
Is the boat too far away?
OR IS IT TOO CLOSE!?
5 Camaros long.
Using the power
of the internet we can find one
of these cars is
Distance = 5 x car length
BUT WAIT! Because we are the best physics 12 students ever, in order to be more accurate we added 1 1/2 Camaro's to distance because
the boat is moving and enlarging the distance.
D = 30.706m
To find the
of the jump we used a simple formula
This is time of the half way so,
1.765s x 2 = real time =
= 59.2 * sin 17 =
= Vi * Cos 17
= 59.2m/s * Cos 17
Time = 3.53s
Vix = 56.61m/s
Distance = 199.84m!!
Thanks for listening!
R.I.P Paul Walker