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Charle's Law

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by

Sarah Baker

on 24 November 2013

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Transcript of Charle's Law

Charles' Law
Step Three
-Without tying the ends of the balloons, place four balloons on top of an open glass bottle.
-Put each bottle and balloon in one of the four pots/bowls.
-Place one balloon in an area at room temperature for a control.
-Let sit for an hour.
Hypothesis
The volume of the balloon will increase when the temperature is increased and the volume will decrease when the temperature is decreased because volume and temperature vary directly according to Charles' law.
Step One
By: Sarah Baker, Megan Snyder, Breanna VanLeuvan, Abby Winters
Step Two
-Place about three cups of water in a pot and heat to 373 Kelvin
-Place about three cups of water in another pot and heat to 368 Kelvin
-Place another three cups of water in a bowl and cool to 277 Kelvin
-Place another three cups of water in a bowl and cool to 275 Kelvin.
-Have area at room temperature (345.5 K)
-Blow up five balloons until the circumference of each is 14.5 inches.
Conclusion
-The conclusion supports our hypothesis.
-At higher temperatures the balloon grew and at lower temperatures the balloon shrunk.
-The balloon in the 275 Kelvin water shrunk 1.5 inches making the circumference 13 inches.
-The balloon on the bottle in the 277 Kelvin water shrunk .5 inches making the circumference 14 inches.
-The balloon on the bottle in the 368 Kelvin water grew 1.25 inches making the circumference 15.75 inches.
-The balloon on the bottle in the 373 Kelvin water grew 1.5 inches making the circumference 16 inches.
Analysis
-When the independent variable (temperature) increased, our dependent variable also increased (volume). When the independent was decreased, the dependent decreased as well.
-If the temperatures were changed the outcome would have been different. If the temperature was higher, the volume would have increased more and if the temperature was lower the volume would have decreased more.
Variables
Independent:Temperature
Dependent: Volume
Control: Pressure
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