SOLVING MATH WORD PROBLEMS Okay, let's write down what we know first in an orderly table: Year 1 2 3 Number of Puppies Produced 2 puppies 1st year multiplied by 3 1st year multiplied by 5 Year

1

2 3 Number of Puppies Produced 2 puppies 1st year multiplied by 5 6 puppies Using background knowledge, we know that 2 (the number of puppies breeded in the first year) multiplied by 3, equals 6. Therefore, we now know that the breeder breeded 6 puppies in the second year. We now have this part of the table filled: In a similar manner as in the previous step, we multiply the number of puppies breeded in the first year with the number of times more puppies were breeded in the third year. 5 times more puppies were breeded in the third year, so our equation is: 2x5=10 Now we know 10 puppies were breeded in the third year:

Year

1

2 3 Number of Puppies Breeded

2 puppies 10 puppies 6 puppies Let's work on solving part A of the problem first! To conclude part A we must find out the answer, by adding the number of puppies the breeder breeded each of the three years altogether. 2 puppies + 6 puppies + 10 puppies = 18 puppies altogether. Ta-da! The answer to the question:

"A)How many puppies will the breeder have produced in her first 3 years?" is:

The breeder will have produced 18 puppies in her first 3 years breeding. I know because: 2 puppies + 6 puppies + 10 puppies = 18 puppies. The strategies I used to answer this word problem are:

1) Mental math

2) Recording information in tables

3) Writing down the information you know to clarify

These three strategies combined are very helpful when solving word problems like this (similar to)! Now let's work on part B of this word problem! STEP #1 STEP #2 STEP #3 STEP #4 ANSWER Breeding Puppies Math Word Problem THE END! Thank you so much for watching! I hope I have helped you figure out how to solve a word problem! There are very many other ways that I have not listed since I did not use them while solving this problem, but are definitely key in other word problems! Some good word problem sites you may want to check out: http://www.mystfx.ca/special/mathproblems/grade5.html & http://www.analyzemath.com/primary_math/grade_5/problems.html Special thanks to

all the UBC students that helped our class with the "Tech with Trek" program! This wouldn't have been possible without them! Part B of the word problem says:

B) If she sells the puppies for $200.00 each, how much will she have made?

We must use background knowledge from part A (the number of puppies she breeded during the 3 year period) to answer this question. Step #1 Again, we organize the information we have in a table: Number of puppies the breeder breeded Amount of money each puppy is sold for $200 18 puppies Step #2 Since the prices of all the puppies are the same, all we have to do now is multiply the number of puppies with the amount of money each puppy is sold for to get the total amount of money the breeder recieved from selling the puppies she breeded during the 3 year period. Our equation:

18x200=$3600 (you should be able to do it as mental math) Answer Ta-da! The answer to the question:

B) If she sells the puppies for $200.00 each, how much will she have made? is:

She will have made $3600 from selling the puppies she breeded during the 3 year period. 18x200=$3600. There, and you have solved a word problem succesfully while showing your work and being time efficient!

-applaud- By Alice W, Age 11, Grade 5, Lord Beaconsfield Elem. ©Copyright 2011 Alice W x = February 15-17 2011 From selling puppies $3600 Number of puppies breeded Word problem final answer:

In her first year, a dog breeder's dogs produce 2 puppies. In her second year, her dogs produce three-times as many puppies. In her third year, her dogs produce 5 times as many puppies as the first year.

A)How many puppies will the breeder have produced in her first 3 years?

Answer: The breeder will have produced 18 puppies in her first 3 years breeding. I know because: 2 puppies + 6 puppies + 10 puppies = 18 puppies.

B) If she sells the puppies for $200.00 each, how much will she have made?

Answer: She will have made $3600 from selling the puppies she breeded during the 3 year period. 18x200=$3600. Best buddies! Two puppies X 5 times more puppies breeded 5 2 = 10 puppies X Two puppies 3 3 times more puppies breeded = 2 6 puppies + + = 10 puppies 2 puppies 6 puppies 18 puppies We need to figure out EXACTLY how many puppies were breeded during the breeder's second and third years, so we can get the total number of puppies he/she breeded. We can do that in the next two steps: breeded in the first year of breeding 2 puppies Aren't we cute? What's up, pals? Come on, let's go! Today I will be showing you how to solve a math word problem like this time efficiently and properly! Special thanks to all the UBC students that helped us with the "Tech with the Trek". This wouldn't have been possible without them! The sample question I am going to be using to demonstrate today is:

In her first year a dog breeder's dogs produce 2 puppies. In her second year her dogs produce 3 times as many puppies. In her third year her dogs produce 5 times as many puppies as the first year.

A)How many puppies will the breeder have produced in her first 3 years?

B) If she sells the puppies for $200.00 each, how much will she have made?

18 200 Special thanks to all the students of UBC that helped our class during the "Tech with Trek" program! ©Copyright 2011 Alice W An ice cream stand has nine different flavours. A group of children come to the stand and each buys a double scoop cone with two flavours of ice cream. If none of the children choose the same combination of flavours, and every different combination of flavors is chosen, how many children are there?

FLAVOURS

1 Vanilla

2 Maple

3 Chocolate

4 Tiger

5 Raspberry

6 Strawberry

7 Coffee

8 Moon Mist

9 Cherry Vanilla Bonus Math Word Problem to try out!

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# How to Solve a Math Word Problem by Alice W

A Prezi "guide" explaining thoroughly how to solve a math word problem correctly and time efficiently! Made during "Tech with Trek" by Alice.

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