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MOJVIMIENTO CIRCULAR

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by

jenny hurtado

on 20 September 2014

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Transcript of MOJVIMIENTO CIRCULAR

MOVIMIENTO CIRCULAR
a) Fuerza que actua sobre el electron
PROBLEMA RESUELTO
En el modelo de Bohr del átomo de hidrógeno, la rapidez del electrón es aproximadamente 2.20 x 10-6 m/s. Encuentre a) la fuerza que actúa sobre el electrón mientras da vueltas en una órbita circular de 0.530 x10-10 m de radio y b) la aceleración centrípeta del electrón.
DATOS
R=0,530x10^(-10) m
V.eletron=2,20x10^(-6) m/s
masa eletron=〖9,1〗^(-31) kg

Fuerza que actúa sobre el electrón
Fc=me.v^2/R=((9,1x10^(-31) kg) ((2,2x10^(-6) m)/s)^2)/(0,530x10^(-10) m)
Fc=((9,1x10^(-31) kg)(4,84x10^(-12) m^2/s^2))/(0,530x10^(-10) m)
Fc (4,4044x10^(-42) kg.m^2/s^2)/(0,530x10^(-10) m)

Fc=8,31x10^(-32) N
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