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OL PH 223 28:1-3

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by

Richard Datwyler

on 25 February 2016

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Transcript of OL PH 223 28:1-3

a proton is released from rest at the positive plate of a parallel plate capacitor. It crosses the capacitor and reaches the negative plate with a speed of 50000m/s. What will be the final speed of an electron released from rest at the negative plate?
What is the electric potential energy of the proton if the electrons are fixed
.5 nm
.5 nm
2 nm
-e
-e
+p
What is the electric potential energy of the group of charges here
3 cm
3 cm
3 cm
-2 nC
-2 nC
+1 nC
What if they were all negative?
PH 121 Speed of a Pendulum

F=ma
Kinematics
Energy !!
A proton is released inside a capacitor that has a constant electric field of 50,000 N/C. If the distance between the charged plates is 0.5 mm, what speed does it reach on impact?
U = 0 J
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